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What is the output of the code shown in Figure 6-104? Dim intAdd As Integer Dim intOuterLoop As Integer Dim intInnerLoop As Integer 8 intAdd = 0 9 For intOuterLoop = 1 To 8 10 For intInnerLoop = 3 To 7 intAdd +- 1 11 12 Next 13 Next 14 MsgBox.Show ("The final value is " & intAdd.ToString()) FIGURE 6-104

What is the output of the code shown in Figure 6-104? Dim intAdd As Integer Dim intOuterLoop As Integer Dim intInnerLoop As Integer 8 intAdd = 0 9 For intOuterLoop = 1 To 8 10 For intInnerLoop = 3 To 7 intAdd +- 1 11 12 Next 13 Next 14 MsgBox.Show ("The final value is " & intAdd.ToString()) FIGURE 6-104

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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The image shows a snippet of Visual Basic code. Here's a detailed transcription: --- **What is the output of the code shown in Figure 6-104?** ```vb 5 Dim intAdd As Integer 6 Dim intOuterLoop As Integer 7 Dim intInnerLoop As Integer 8 intAdd = 0 9 For intOuterLoop = 1 To 8 10 For intInnerLoop = 3 To 7 11 intAdd += 1 12 Next 13 Next 14 MsgBox.Show("The final value is " & intAdd.ToString()) ``` *FIGURE 6-104* --- **Explanation of the Code:** 1. **Declaration:** - The code declares three integer variables: `intAdd`, `intOuterLoop`, and `intInnerLoop`. 2. **Initialization:** - The variable `intAdd` is initialized to 0. 3. **Nested Loops:** - An outer loop runs from 1 to 8. - An inner loop runs from 3 to 7. - Inside the inner loop, `intAdd` is incremented by 1. 4. **Calculation:** - For each iteration of the outer loop (8 iterations total), the inner loop runs 5 times (from 3 to 7). - Therefore, the total number of times `intAdd` is incremented is \(8 \times 5 = 40\). 5. **Output:** - A message box displays: "The final value is 40".
Transcribed Image Text:The image shows a snippet of Visual Basic code. Here's a detailed transcription: --- **What is the output of the code shown in Figure 6-104?** ```vb 5 Dim intAdd As Integer 6 Dim intOuterLoop As Integer 7 Dim intInnerLoop As Integer 8 intAdd = 0 9 For intOuterLoop = 1 To 8 10 For intInnerLoop = 3 To 7 11 intAdd += 1 12 Next 13 Next 14 MsgBox.Show("The final value is " & intAdd.ToString()) ``` *FIGURE 6-104* --- **Explanation of the Code:** 1. **Declaration:** - The code declares three integer variables: `intAdd`, `intOuterLoop`, and `intInnerLoop`. 2. **Initialization:** - The variable `intAdd` is initialized to 0. 3. **Nested Loops:** - An outer loop runs from 1 to 8. - An inner loop runs from 3 to 7. - Inside the inner loop, `intAdd` is incremented by 1. 4. **Calculation:** - For each iteration of the outer loop (8 iterations total), the inner loop runs 5 times (from 3 to 7). - Therefore, the total number of times `intAdd` is incremented is \(8 \times 5 = 40\). 5. **Output:** - A message box displays: "The final value is 40".
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