What is the output of: SELECT city, COUNT(id) As CountPerCity FROM employees e group by city HAVING city like 'A%' a. O b. O c. O d. 1 2 A 1 2 35 GAW 4 6 7 A 1 2 D ABC city Albany Austin 23456 ABC city Albany Austin Fargo Indianapolis Jacksonville North Las Vegas Portland ABC City Albany Austin ABC city 1 Albany Austin Fargo Fort Worth Gilbert CountPerCity T Indianapolis 7 Jacksonville 8 Little Rock 123 T 123 T 123 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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4A-

What is the output of:
SELECT city, COUNT(id) As CountPerCity FROM employees e
group by city
HAVING city like 'A%'
a.
O b.
O C.
ABC city
1 Albany
2
Austin
ABC city
1 Albany
-~3456
2
7
·
1
2
O d. D
-~34|5|67|00
1
Austin
Fargo
Indianapolis
Jacksonville
ABC city
Albany
2 Austin
8
ABC city
Albany
Austin
North Las Vegas
Portland
Fargo
Fort Worth
Gilbert
CountPerCity T
Indianapolis
Jacksonville
Little Rock
T 123
123
123
1
1
1
1
1
1
1
1
1
1
1
1
1
1
1
1
1
1
Transcribed Image Text:What is the output of: SELECT city, COUNT(id) As CountPerCity FROM employees e group by city HAVING city like 'A%' a. O b. O C. ABC city 1 Albany 2 Austin ABC city 1 Albany -~3456 2 7 · 1 2 O d. D -~34|5|67|00 1 Austin Fargo Indianapolis Jacksonville ABC city Albany 2 Austin 8 ABC city Albany Austin North Las Vegas Portland Fargo Fort Worth Gilbert CountPerCity T Indianapolis Jacksonville Little Rock T 123 123 123 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
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