What is the output from the code snippet below? int* index [5]; int data [10] = {4, 8, 1, 3, 5, 9, 3, 2, 6, 0}; int i = 0; int* p = &data[0]; for (int i = 0; i < 5; i++) { index[i] = p; p++; } for (int i = 0; i < 5; i++) { cout << *index [i] << " "; } 48135 53184 06239 93260

C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter7: Arrays
Section: Chapter Questions
Problem 4PP: (Numerical) Write and test a function that returns the position of the largest and smallest values...
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**Code Snippet Output Explanation**

Here is the provided code snippet:

```cpp
int* index[5];
int data[10] = {4, 8, 1, 3, 5, 9, 3, 2, 6, 0};
int i = 0;
int* p = &data[0];
for (int i = 0; i < 5; i++)
{
    index[i] = p;
    p++;
}
for (int i = 0; i < 5; i++)
{
    cout << *index[i] << " ";
}
```

**Explanation of Code:**

1. **Initialization:**
   - `int* index[5];`: An array of 5 integer pointers is declared.
   - `int data[10] = {4, 8, 1, 3, 5, 9, 3, 2, 6, 0};`: An array of 10 integers is initialized with specific values.

2. **Pointer Initialization:**
   - `int* p = &data[0];`: A pointer `p` is initialized to point to the first element of the `data` array.

3. **First `for` Loop:**
   - This loop iterates 5 times (`i` from 0 to 4).
   - During each iteration, `index[i]` is assigned the current address `p` is pointing to.
   - Then, the pointer `p` is incremented to point to the next element of the `data` array.

4. **Second `for` Loop:**
   - This loop also iterates 5 times (`i` from 0 to 4).
   - During each iteration, the value at the address stored in `index[i]` is printed.

**Output:**
- The `index` array ends up storing pointers to the first 5 elements of the `data` array: `4, 8, 1, 3, 5`.
- Thus, the output of the code will be:

```
4 8 1 3 5
```

**Answer Choices:**
1. 48135
2. 53184
3. 06239
4. 93260

The correct answer is **48135**.
Transcribed Image Text:**Code Snippet Output Explanation** Here is the provided code snippet: ```cpp int* index[5]; int data[10] = {4, 8, 1, 3, 5, 9, 3, 2, 6, 0}; int i = 0; int* p = &data[0]; for (int i = 0; i < 5; i++) { index[i] = p; p++; } for (int i = 0; i < 5; i++) { cout << *index[i] << " "; } ``` **Explanation of Code:** 1. **Initialization:** - `int* index[5];`: An array of 5 integer pointers is declared. - `int data[10] = {4, 8, 1, 3, 5, 9, 3, 2, 6, 0};`: An array of 10 integers is initialized with specific values. 2. **Pointer Initialization:** - `int* p = &data[0];`: A pointer `p` is initialized to point to the first element of the `data` array. 3. **First `for` Loop:** - This loop iterates 5 times (`i` from 0 to 4). - During each iteration, `index[i]` is assigned the current address `p` is pointing to. - Then, the pointer `p` is incremented to point to the next element of the `data` array. 4. **Second `for` Loop:** - This loop also iterates 5 times (`i` from 0 to 4). - During each iteration, the value at the address stored in `index[i]` is printed. **Output:** - The `index` array ends up storing pointers to the first 5 elements of the `data` array: `4, 8, 1, 3, 5`. - Thus, the output of the code will be: ``` 4 8 1 3 5 ``` **Answer Choices:** 1. 48135 2. 53184 3. 06239 4. 93260 The correct answer is **48135**.
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ISBN:
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Publisher:
Course Technology Ptr