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What is the number of molecules in 256g of Li3PO4? OA 1.46 x 10-24 O B. 1.46 x 1023 OC. 1.46 x 10-23 O D. 1.46 x 1024

What is the number of molecules in 256g of Li3PO4? OA 1.46 x 10-24 O B. 1.46 x 1023 OC. 1.46 x 10-23 O D. 1.46 x 1024

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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B/CHEM1100Fundamentals Of Chemistry/3 board / My courses / 53/CHEM1100/3/ Topic 16 / CHEM1100 Fundamentals of Chemistry S3 Final Exam Dec.202 25 What is the number of molecules in 256g of LizPO4? OA 1.46 x 10-24 ut of OB. 1.46 x 1023 estion OC 1.46 x 10-23 O D. 1.46 x 1024 age SSION EXP-4 Jump to.
Transcribed Image Text:B/CHEM1100Fundamentals Of Chemistry/3 board / My courses / 53/CHEM1100/3/ Topic 16 / CHEM1100 Fundamentals of Chemistry S3 Final Exam Dec.202 25 What is the number of molecules in 256g of LizPO4? OA 1.46 x 10-24 ut of OB. 1.46 x 1023 estion OC 1.46 x 10-23 O D. 1.46 x 1024 age SSION EXP-4 Jump to.
Expert Solution
Basic

1 mole of compound contain 6.022×1023 molecules .

1 mole = 6.022×1023 molecules 

To find the number of Molecules present in Li3PO4 , first we have to convert the mass of Li3PO4 into moles .

From this moles we can  find out the number of molecule in 256 g of Li3PO4 .

Mass of Li3PO4 = 256 g

Molar mass of Li3PO4 = 115.79 g/mol

Step by step solution

( mole = mass / molar mass )

Moles of Li3PO4 

= Mass of Li3PO4 / molar mass of Li3PO4

= 256 g / 115.79 g/mol

= 2.21 mol

 

Number of Moles of Li3PO4 = 2.21 mol

As we know , 

1 mole = 6.022×1023 molecules 

So, ( Li3PO4 ) 2.21 mol contain

= 6.022×1023 molecules ×  2.21

= 1.34 × 1024 Molecules

This answer is nearly equal to ~

1.46 × 1024 molecules

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