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What is the new volume (in mL) of a gas that is reduced from a temperature of 651 K to 298 K if its initial volume was 215 mL?

What is the new volume (in mL) of a gas that is reduced from a temperature of 651 K to 298 K if its initial volume was 215 mL?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Problem Statement:** What is the new volume (in mL) of a gas that is reduced from a temperature of 651 K to 298 K if its initial volume was 215 mL? **Explanation:** To solve this problem, you can use the ideal gas law under the assumption that pressure and the amount of gas remain constant. According to Charles's Law (V1/T1 = V2/T2), the volume of a gas is directly proportional to its temperature in Kelvin. **Given:** - Initial Volume (V1) = 215 mL - Initial Temperature (T1) = 651 K - Final Temperature (T2) = 298 K **Formula:** V1/T1 = V2/T2 Solving for the Final Volume (V2): V2 = V1 × (T2/T1) **Calculation:** V2 = 215 mL × (298 K / 651 K) = 98.46 mL Hence, the new volume of the gas is approximately 98.46 mL.
Transcribed Image Text:**Problem Statement:** What is the new volume (in mL) of a gas that is reduced from a temperature of 651 K to 298 K if its initial volume was 215 mL? **Explanation:** To solve this problem, you can use the ideal gas law under the assumption that pressure and the amount of gas remain constant. According to Charles's Law (V1/T1 = V2/T2), the volume of a gas is directly proportional to its temperature in Kelvin. **Given:** - Initial Volume (V1) = 215 mL - Initial Temperature (T1) = 651 K - Final Temperature (T2) = 298 K **Formula:** V1/T1 = V2/T2 Solving for the Final Volume (V2): V2 = V1 × (T2/T1) **Calculation:** V2 = 215 mL × (298 K / 651 K) = 98.46 mL Hence, the new volume of the gas is approximately 98.46 mL.
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