What is the net force Fret on an airplane window of area 1400 cm2 if the pressure inside the cabin is 0.95 atm and the pressure outside is 0.76 atm? Fnet =
What is the net force Fret on an airplane window of area 1400 cm2 if the pressure inside the cabin is 0.95 atm and the pressure outside is 0.76 atm? Fnet =
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![**Problem: Determining the Net Force on an Airplane Window**
**Question:**
What is the net force \( F_{\text{net}} \) on an airplane window of area 1400 cm\(^2\) if the pressure inside the cabin is 0.95 atm and the pressure outside is 0.76 atm?
**Solution Area:**
\[ F_{\text{net}} = \]
[Box for answer]
**Units:** N (Newtons)
### Explanation:
To find the net force acting on the airplane window, we need to calculate the difference in pressure between the inside and outside of the cabin and apply it to the area of the window.
1. **Convert the area from cm² to m²**:
\[
1400 \, \text{cm}^2 = 0.14 \, \text{m}^2
\]
2. **Calculate the pressure difference (\(\Delta P\))**:
\[
\Delta P = P_{\text{inside}} - P_{\text{outside}} = 0.95 \, \text{atm} - 0.76 \, \text{atm} = 0.19 \, \text{atm}
\]
3. **Convert the pressure difference from atm to Pascals (Pa)**:
\[
1 \, \text{atm} = 101325 \, \text{Pa}
\]
\[
\Delta P = 0.19 \times 101325 \, \text{Pa} = 19251.75 \, \text{Pa}
\]
4. **Use the formula for force due to pressure difference**:
\[
F_{\text{net}} = \Delta P \times \text{Area} = 19251.75 \, \text{Pa} \times 0.14 \, \text{m}^2
\]
\[
F_{\text{net}} = 2695.245 \, \text{N}
\]
The net force acting on the window is approximately \(2695.25 \, \text{N}\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe496cfb4-14de-4877-8074-43f9c7c49581%2F74bb65aa-ab1e-439f-8235-650a562bf9d3%2Fz75zexv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem: Determining the Net Force on an Airplane Window**
**Question:**
What is the net force \( F_{\text{net}} \) on an airplane window of area 1400 cm\(^2\) if the pressure inside the cabin is 0.95 atm and the pressure outside is 0.76 atm?
**Solution Area:**
\[ F_{\text{net}} = \]
[Box for answer]
**Units:** N (Newtons)
### Explanation:
To find the net force acting on the airplane window, we need to calculate the difference in pressure between the inside and outside of the cabin and apply it to the area of the window.
1. **Convert the area from cm² to m²**:
\[
1400 \, \text{cm}^2 = 0.14 \, \text{m}^2
\]
2. **Calculate the pressure difference (\(\Delta P\))**:
\[
\Delta P = P_{\text{inside}} - P_{\text{outside}} = 0.95 \, \text{atm} - 0.76 \, \text{atm} = 0.19 \, \text{atm}
\]
3. **Convert the pressure difference from atm to Pascals (Pa)**:
\[
1 \, \text{atm} = 101325 \, \text{Pa}
\]
\[
\Delta P = 0.19 \times 101325 \, \text{Pa} = 19251.75 \, \text{Pa}
\]
4. **Use the formula for force due to pressure difference**:
\[
F_{\text{net}} = \Delta P \times \text{Area} = 19251.75 \, \text{Pa} \times 0.14 \, \text{m}^2
\]
\[
F_{\text{net}} = 2695.245 \, \text{N}
\]
The net force acting on the window is approximately \(2695.25 \, \text{N}\).
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