What is the net force acting on the object according to the system in the figure? (Surface charge density is 8.85.10^(-9) C/m^2, q= 4.10^(-3)C)=8,85.10° C/m?53053035 -T=10 NT=10Nq=+ 4,10°COa) 52OB) 4O NS) one thousandD) oneO TO) O

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Answered: What is the net force acting on the…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Arrange three charges in form of equilateral triangle as shown in figure and find the force q3 due to other two (take k=9*10° Nm?/C?). y (m) 2+ 93 = 5.0x 10-“c 92 = -2.0*10-6 C 91 = 2.0 x 10-°C 2 * (m) 1
I need the answer in No. 11 but it is connected to the answer in the problem above. Please?
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise A proton accelerates from rest in a uniform electric field of 663 N/C. At some later time, its speed is 1.29 x 106 m/s. (a) Find the magnitude of the acceleration of the proton. (b) How long does it take the proton to reach this speed? (c) How far has it moved in that interval? (d) What is its kinetic energy at the later time? Step 1 eE (a) The force exerted on the proton of charge qp = +e by the electric field has magnitude F = q E = EE where E is the magnitude of the electric field and F is the magnitude of the force. ap Newton's second law gives the acceleration a of the proton in terms of its charge and mass m, as a = F eE Mp Mp (1.60 x 10-19, = = 6.35 663✔ 9c)(663 1.673 x 10-27 kg) 6.34 x 1010 m/s². 663 N/C) 1 kg. m/s² 1 N
Hint:You will use a certain law in trigonometry twice. Answer must be 934,531 Newtons
Three charges are placed along the x-axis: q1 = 3.00 µC at X1 = -20.0 cm, q2 = -5.00 µC at x2 = 10.0 cm, and q3 = 6.00 µC at x3 = 25.00 cm. Determine the magnitude of the electric field at the origin. O 4 69x106 N/C O 2 96x106 N/C O 6 04x106 N/C O 4.31x106 N/C
Two spheres with equal charges, q1 and q2, are separated by a distance, r, and repel each other as shown. r = 1.00 x 10-2 m and F2 = + 9.00 x 10-5 N. The charge on a single charge is 1.6 x 10-19 C. The charge q1 (in C) is equal to 2.00 x 10-9 0 4.00 x 10-9 1.00 x 10-9
Consider two point charges located at the corners of a square with a side length a = 20 cm as shown in the following figure, where q1 = 5 µC. and q2 = -10 µC. y 20 cm 92 k----- 20 cm -----> The vector electric field (2 ) that q, and q2 together create at point P is Оa. (2.41 — 3.8)х 109]N/C O b. [(0.8î – 1.45) × 10ʻ]N/C O. [(0.4î – 1.85) × 10ʻ]N/C O d. [(1.8î – 0.45) × 10°]N/C
pls answer 1,2,3
Three charges are placed on three corners if a square, as shown in the figure. Each side of the square is 24.0 cm. Compute the magnitude and direction of the net electric field at the fourth corner as shown ( initially, electric field due to each change is given).
homework 1, 1b. Dont know what im doing wrong
Questions 8-10 refer to the figure below. 91 а 92 а а 94 а 93 8. Four charges q1 = of the square have a length a. In terms of ke, Q, and a calculate the electric force acting on q1 due to q2, 93, and +Q, q2 = +Q, 93 = –Q, and q4 = -Q are in the corners of a square. The sides 4. A. ke (-0.65ây – 1.35g) C. kQ (0.65 + 1.35ŷ) В. К(-1.352 — 0.659) D. k (1.35â + 0.65ý) a2 a2 9. Four charges q1 = +Q, q2 = +Q, q3 = -Q, and q4 = -Q are in the corners of a square. The sides of the square have a length a. In terms of ke, Q, and a calculate the electric force acting on 2 due to q1, 93, and q4. A. k (0.65â – 1.35ŷ) C. E(-0.65£ + 1.35ŷ) D. g(-1,35 + 0.65ý) Q² B. k (1.35â – 0.65ý) 10. Four charges q1 = +Q, q2 = +Q, q3 = -Q, and q4 = -Q are in the corners of a square. The sides of the square have a length a. In terms of ke, Q, and a calculate the electric force acting on q3 due to q1, 92, and q4. A. k(-0.65â – 1.35g) B. k(-1.35â – 0.65ŷ) D. ke (1.35€ + 0.65ŷ) С. К (0.65 + 1.35)
Calculate the magnitude of the force on the charge q, given that the square made by the charges is 11.2 cm on a side and q= 2.10 μC . qa=qb= 7.60μC and qc=qd= -7.60 μC

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What is the net force acting on the object according to the system in the figure? (Surface charge density is 8.85.10^(-9) C/m^2, q= 4.10^(-3)C) =8,85.10° C/m² 53 530 T=10 N T=10N q=+ 4,10°C Oa) 5.2 OB) 4 ONS) one thousand