Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Calculating Molarity of a Sodium Chloride (NaCl) Solution**
When 159 grams of NaCl is dissolved in sufficient water to prepare a 1.86 L solution, the molarity of the solution can be calculated using the provided information and the formula for molarity.
### Given Data:
- **Mass of NaCl (g)**: 159 g
- **Volume of solution (L)**: 1.86 L
- **Molar mass of NaCl (g/mol)**: 58.44 g/mol
### Steps to Calculate Molarity:
1. **Determine the number of moles of NaCl:**
- Use the formula:
\[
\text{moles of NaCl} = \frac{\text{mass of NaCl}}{\text{molar mass of NaCl}}
\]
- Calculation:
\[
\text{moles of NaCl} = \frac{159 \text{ g}}{58.44 \text{ g/mol}} = 2.72 \text{ moles}
\]
2. **Calculate the molarity (M) of the solution:**
- Use the formula:
\[
\text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}}
\]
- Calculation:
\[
\text{Molarity (M)} = \frac{2.72 \text{ moles}}{1.86 \text{ L}} = 1.46
\]
### Important Notes:
- **Round** the final answer to the hundredths place. If needed, include trailing zeros.
- **Do NOT include units** in the final answer as specified in instructions.
Thus, the molarity of the NaCl solution is **1.46**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F959a643c-45ff-4cba-bf81-f285af0e5e62%2F3e88d725-c9ab-4537-bd32-88e443282383%2F36k7zyh_processed.png&w=3840&q=75)
Transcribed Image Text:**Calculating Molarity of a Sodium Chloride (NaCl) Solution**
When 159 grams of NaCl is dissolved in sufficient water to prepare a 1.86 L solution, the molarity of the solution can be calculated using the provided information and the formula for molarity.
### Given Data:
- **Mass of NaCl (g)**: 159 g
- **Volume of solution (L)**: 1.86 L
- **Molar mass of NaCl (g/mol)**: 58.44 g/mol
### Steps to Calculate Molarity:
1. **Determine the number of moles of NaCl:**
- Use the formula:
\[
\text{moles of NaCl} = \frac{\text{mass of NaCl}}{\text{molar mass of NaCl}}
\]
- Calculation:
\[
\text{moles of NaCl} = \frac{159 \text{ g}}{58.44 \text{ g/mol}} = 2.72 \text{ moles}
\]
2. **Calculate the molarity (M) of the solution:**
- Use the formula:
\[
\text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}}
\]
- Calculation:
\[
\text{Molarity (M)} = \frac{2.72 \text{ moles}}{1.86 \text{ L}} = 1.46
\]
### Important Notes:
- **Round** the final answer to the hundredths place. If needed, include trailing zeros.
- **Do NOT include units** in the final answer as specified in instructions.
Thus, the molarity of the NaCl solution is **1.46**.
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