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What is the molarity of ions in a 0.859 M solution of Ca(OH)2 assuming the compound dissociates completely?

What is the molarity of ions in a 0.859 M solution of Ca(OH)2 assuming the compound dissociates completely?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:** What is the molarity of ions in a 0.850 M solution of Ca(OH)₂, assuming the compound dissociates completely? **Explanation:** When calcium hydroxide, Ca(OH)₂, dissociates completely in water, it breaks down into one calcium ion (Ca²⁺) and two hydroxide ions (OH⁻). Therefore, for every mole of Ca(OH)₂, one mole of Ca²⁺ and two moles of OH⁻ ions are produced. Given that the molarity of the Ca(OH)₂ solution is 0.850 M: - The concentration of Ca²⁺ ions will be the same as the molarity of Ca(OH)₂: 0.850 M. - The concentration of OH⁻ ions will be twice that of Ca(OH)₂ because each formula unit of Ca(OH)₂ produces two hydroxide ions: 2 × 0.850 M = 1.700 M. **Total ion concentration:** 0.850 M (Ca²⁺) + 1.700 M (OH⁻) = 2.550 M **Calculator Interface:** There is a digital calculator interface on the screen with numbers 0-9, arithmetic operation buttons, a "C" for clear, a "±" button to toggle between positive and negative values, and an "x 10ⁿ" button for scientific notation. Overall, the solution introduces how to calculate the molarity of ions by considering the dissociation of the compound in question.
Transcribed Image Text:**Question:** What is the molarity of ions in a 0.850 M solution of Ca(OH)₂, assuming the compound dissociates completely? **Explanation:** When calcium hydroxide, Ca(OH)₂, dissociates completely in water, it breaks down into one calcium ion (Ca²⁺) and two hydroxide ions (OH⁻). Therefore, for every mole of Ca(OH)₂, one mole of Ca²⁺ and two moles of OH⁻ ions are produced. Given that the molarity of the Ca(OH)₂ solution is 0.850 M: - The concentration of Ca²⁺ ions will be the same as the molarity of Ca(OH)₂: 0.850 M. - The concentration of OH⁻ ions will be twice that of Ca(OH)₂ because each formula unit of Ca(OH)₂ produces two hydroxide ions: 2 × 0.850 M = 1.700 M. **Total ion concentration:** 0.850 M (Ca²⁺) + 1.700 M (OH⁻) = 2.550 M **Calculator Interface:** There is a digital calculator interface on the screen with numbers 0-9, arithmetic operation buttons, a "C" for clear, a "±" button to toggle between positive and negative values, and an "x 10ⁿ" button for scientific notation. Overall, the solution introduces how to calculate the molarity of ions by considering the dissociation of the compound in question.
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