What is the molar solubility of Ca3(PO4)2 at 25°C? Ksp = 1.3 x 10-33 at 25°C Question 1 options: 1.0 x 10-7 M Ca3(PO4)2 3.6 x 10-17 M Ca3(PO4)2 7.4 x 10-17 M Ca3(PO4)2 1.3 x 10-7 M Ca3(PO4)2 2.6 x 10-7 M Ca3(PO4)2 1.8 x 10-7 M Ca3(PO4)2 8.7 x 10-17 M Ca3(PO4)2 1.7 x 10-17 M Ca3(PO4)2
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Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
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What is the molar solubility of Ca3(PO4)2 at 25°C?
Ksp = 1.3 x 10-33 at 25°C
Question 1 options:
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1.0 x 10-7 M Ca3(PO4)2 |
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3.6 x 10-17 M Ca3(PO4)2 |
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7.4 x 10-17 M Ca3(PO4)2 |
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1.3 x 10-7 M Ca3(PO4)2 |
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2.6 x 10-7 M Ca3(PO4)2 |
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1.8 x 10-7 M Ca3(PO4)2 |
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8.7 x 10-17 M Ca3(PO4)2 |
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1.7 x 10-17 M Ca3(PO4)2 |
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