What is the molality of a solution containing 50.0 g of NaCl (58.44 g/mol) dissolved in 2.50 kg of water? b) How many grams of Na2SO4 (142.04 g/mol) needs to 1.5 kg of water to make a 0.500 mol/kg water solution
What is the molality of a solution containing 50.0 g of NaCl (58.44 g/mol) dissolved in 2.50 kg of water?
b) How many grams of Na2SO4 (142.04 g/mol) needs to 1.5 kg of water to make a 0.500 mol/kg water solution
Molality is defined as the “total moles of a solute contained in a kilogram of a solvent.”
Molality = Number of moles of solute / Mass of solvent in kg
molality is represented by m
Unit of molality = molal or moles per kg of solvent
50.0 g of NaCl (58.44 g/mol) dissolved in 2.50 kg of water?
Solution :-
first we will calculate moles of solute
mass of NaCl = 50.0 g
molar mass of NaCl = 58.44 g/mol
moles of NaCl = mass of NaCl / molar mass of NaCl
= 50.0g / 58.44 g/mol
=0.86moles
mass of water ( solvent ) = 2.50 kg
molality = Number of moles of solute / Mass of solvent in kg
=0.86 moles of NaCl / 2.50kg of water
= 0.344 molal
Answer :- molality of a solution containing 50.0 g of NaCl (58.44 g/mol) dissolved in 2.50 kg of water is = 0.344 molal
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