What is the molality of a solution composed of 106 g of acetone ((CH3)2CO) dissolved in 225 g of water? The molar mass of acetone is 58.08 g/mol. [?] mol/kg Enter Molality of Acetone
What is the molality of a solution composed of 106 g of acetone ((CH3)2CO) dissolved in 225 g of water? The molar mass of acetone is 58.08 g/mol. [?] mol/kg Enter Molality of Acetone
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem: Calculating the Molality of a Solution**
**Question:**
What is the molality of a solution composed of 106 g of acetone ((CH₃)₂CO) dissolved in 225 g of water? The molar mass of acetone is 58.08 g/mol.
**Solution:**
To find the molality (m) of the solution, use the formula:
\[ m = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}} \]
Step 1: Calculate the moles of acetone.
Given:
- Mass of acetone (solute) = 106 g
- Molar mass of acetone = 58.08 g/mol
Using the formula:
\[ \text{moles of acetone} = \frac{\text{mass of acetone}}{\text{molar mass of acetone}} \]
\[ \text{moles of acetone} = \frac{106 \, \text{g}}{58.08 \, \text{g/mol}} \]
\[ \text{moles of acetone} = 1.8267 \, \text{mol} \]
Step 2: Convert the mass of solvent from grams to kilograms.
Given:
- Mass of water (solvent) = 225 g
\[ \text{mass of solvent in kg} = \frac{225 \, \text{g}}{1000} \]
\[ \text{mass of solvent in kg} = 0.225 \, \text{kg} \]
Step 3: Substitute the values to find the molality.
\[ m = \frac{1.8267 \, \text{mol}}{0.225 \, \text{kg}} \]
\[ m = 8.119 \, \text{mol/kg} \]
**Conclusion:** The molality of the acetone solution is approximately 8.12 mol/kg.
**Visual Aid Description:**
Underneath the question and calculations, there is an interactive tool labeled "Molality of Acetone" with an input box where users can enter their calculated value followed by an "Enter" button to confirm their answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F90e77b90-a4df-4db6-b7ee-6d19627c35a4%2Fab2633ee-47dd-42e9-acaf-7442a96dddb6%2F2gblphq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem: Calculating the Molality of a Solution**
**Question:**
What is the molality of a solution composed of 106 g of acetone ((CH₃)₂CO) dissolved in 225 g of water? The molar mass of acetone is 58.08 g/mol.
**Solution:**
To find the molality (m) of the solution, use the formula:
\[ m = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}} \]
Step 1: Calculate the moles of acetone.
Given:
- Mass of acetone (solute) = 106 g
- Molar mass of acetone = 58.08 g/mol
Using the formula:
\[ \text{moles of acetone} = \frac{\text{mass of acetone}}{\text{molar mass of acetone}} \]
\[ \text{moles of acetone} = \frac{106 \, \text{g}}{58.08 \, \text{g/mol}} \]
\[ \text{moles of acetone} = 1.8267 \, \text{mol} \]
Step 2: Convert the mass of solvent from grams to kilograms.
Given:
- Mass of water (solvent) = 225 g
\[ \text{mass of solvent in kg} = \frac{225 \, \text{g}}{1000} \]
\[ \text{mass of solvent in kg} = 0.225 \, \text{kg} \]
Step 3: Substitute the values to find the molality.
\[ m = \frac{1.8267 \, \text{mol}}{0.225 \, \text{kg}} \]
\[ m = 8.119 \, \text{mol/kg} \]
**Conclusion:** The molality of the acetone solution is approximately 8.12 mol/kg.
**Visual Aid Description:**
Underneath the question and calculations, there is an interactive tool labeled "Molality of Acetone" with an input box where users can enter their calculated value followed by an "Enter" button to confirm their answer.
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