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What is the mass percent of 1.39 M NaCl solution? The density of this solution is 1.05 g/ml

What is the mass percent of 1.39 M NaCl solution? The density of this solution is 1.05 g/ml

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Chemistry Problem: Calculation of Mass Percent** **Problem:** What is the mass percent of 1.39 M NaCl solution? The density of this solution is 1.05 g/mL. --- To solve this problem, students will need to follow the concept of mass percent calculation. The guiding equation involves determining the mass of the solute (NaCl) and the mass of the solution and then expressing this ratio as a percentage. Mass percent (%) = (mass of solute / mass of solution) x 100 1. **Step 1: Determine the mass of the solute (NaCl).** - A 1 M solution contains 1 mole of solute per liter of solution. Therefore, a 1.39 M NaCl solution contains 1.39 moles of NaCl per liter. - Molar mass of NaCl = 58.44 g/mol (Sodium (Na) = 22.99 g/mol, Chlorine (Cl) = 35.45 g/mol). - Mass of NaCl in 1 liter = 1.39 moles * 58.44 g/mol = 81.2276 g. 2. **Step 2: Determine the mass of the solution.** - Density (d) = mass/volume. The density of the NaCl solution is given as 1.05 g/mL. - For 1 liter of solution (which is 1000 mL), the mass of the solution = 1.05 g/mL * 1000 mL = 1050 g. 3. **Step 3: Calculate the mass percent.** - Mass percent of NaCl = (mass of NaCl / mass of solution) * 100 - Mass percent = (81.2276 g / 1050 g) * 100 ≈ 7.73% Therefore, the mass percent of the 1.39 M NaCl solution is approximately 7.73%.
Transcribed Image Text:**Chemistry Problem: Calculation of Mass Percent** **Problem:** What is the mass percent of 1.39 M NaCl solution? The density of this solution is 1.05 g/mL. --- To solve this problem, students will need to follow the concept of mass percent calculation. The guiding equation involves determining the mass of the solute (NaCl) and the mass of the solution and then expressing this ratio as a percentage. Mass percent (%) = (mass of solute / mass of solution) x 100 1. **Step 1: Determine the mass of the solute (NaCl).** - A 1 M solution contains 1 mole of solute per liter of solution. Therefore, a 1.39 M NaCl solution contains 1.39 moles of NaCl per liter. - Molar mass of NaCl = 58.44 g/mol (Sodium (Na) = 22.99 g/mol, Chlorine (Cl) = 35.45 g/mol). - Mass of NaCl in 1 liter = 1.39 moles * 58.44 g/mol = 81.2276 g. 2. **Step 2: Determine the mass of the solution.** - Density (d) = mass/volume. The density of the NaCl solution is given as 1.05 g/mL. - For 1 liter of solution (which is 1000 mL), the mass of the solution = 1.05 g/mL * 1000 mL = 1050 g. 3. **Step 3: Calculate the mass percent.** - Mass percent of NaCl = (mass of NaCl / mass of solution) * 100 - Mass percent = (81.2276 g / 1050 g) * 100 ≈ 7.73% Therefore, the mass percent of the 1.39 M NaCl solution is approximately 7.73%.
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