**Chemistry Problem: Calculation of Mass Percent****Problem:**What is the mass percent of 1.39 M NaCl solution? The density of this solution is 1.05 g/mL.---To solve this problem, students will need to follow the concept of mass percent calculation. The guiding equation involves determining the mass of the solute (NaCl) and the mass of the solution and then expressing this ratio as a percentage.Mass percent (%) = (mass of solute / mass of solution) x 1001. **Step 1: Determine the mass of the solute (NaCl).** - A 1 M solution contains 1 mole of solute per liter of solution. Therefore, a 1.39 M NaCl solution contains 1.39 moles of NaCl per liter. - Molar mass of NaCl = 58.44 g/mol (Sodium (Na) = 22.99 g/mol, Chlorine (Cl) = 35.45 g/mol). - Mass of NaCl in 1 liter = 1.39 moles * 58.44 g/mol = 81.2276 g.2. **Step 2: Determine the mass of the solution.** - Density (d) = mass/volume. The density of the NaCl solution is given as 1.05 g/mL. - For 1 liter of solution (which is 1000 mL), the mass of the solution = 1.05 g/mL * 1000 mL = 1050 g.3. **Step 3: Calculate the mass percent.** - Mass percent of NaCl = (mass of NaCl / mass of solution) * 100 - Mass percent = (81.2276 g / 1050 g) * 100 ≈ 7.73%Therefore, the mass percent of the 1.39 M NaCl solution is approximately 7.73%.

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What is the mass percent of 1.39 M NaCl solution? The density of this solution is 1.05 g/ml

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

**Chemistry Problem: Calculation of Mass Percent**

**Problem:**

What is the mass percent of 1.39 M NaCl solution? The density of this solution is 1.05 g/mL.

---

To solve this problem, students will need to follow the concept of mass percent calculation. The guiding equation involves determining the mass of the solute (NaCl) and the mass of the solution and then expressing this ratio as a percentage.

Mass percent (%) = (mass of solute / mass of solution) x 100

1. **Step 1: Determine the mass of the solute (NaCl).**
- A 1 M solution contains 1 mole of solute per liter of solution. Therefore, a 1.39 M NaCl solution contains 1.39 moles of NaCl per liter.
- Molar mass of NaCl = 58.44 g/mol (Sodium (Na) = 22.99 g/mol, Chlorine (Cl) = 35.45 g/mol).
- Mass of NaCl in 1 liter = 1.39 moles * 58.44 g/mol = 81.2276 g.

2. **Step 2: Determine the mass of the solution.**
- Density (d) = mass/volume. The density of the NaCl solution is given as 1.05 g/mL.
- For 1 liter of solution (which is 1000 mL), the mass of the solution = 1.05 g/mL * 1000 mL = 1050 g.

3. **Step 3: Calculate the mass percent.**
- Mass percent of NaCl = (mass of NaCl / mass of solution) * 100
- Mass percent = (81.2276 g / 1050 g) * 100 ≈ 7.73%

Therefore, the mass percent of the 1.39 M NaCl solution is approximately 7.73%.

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