What is the mass of 9.45 moles of Al2O3? After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion: 1 mole Al, 0, 9.45 moles Al2O3* 102.2 grams of Al, O₂ Is this answer correct? = 0.0926 grams of Al₂O3
What is the mass of 9.45 moles of Al2O3? After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion: 1 mole Al, 0, 9.45 moles Al2O3* 102.2 grams of Al, O₂ Is this answer correct? = 0.0926 grams of Al₂O3
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Include a CLAIM: answer the question. Is this correct or not?
Include EVIDENCE: Describe what you see in the calculation work that supports your claim.
Include REASONING: Explain WHY you selected that evidence to support your claim.
Hint attached.

Transcribed Image Text:A
1 mole = 6.02 x 10²³ particles
✓
N
6.02 x 10 particles
1 mole
C
6.02 x 10¹ particles
B 1 mole = molar mass* (grams)
"S
determined by summing the ma 1 of all elements in the formula
1 mole = 22.4 L of gas
Inde
7241
22.4 L

Transcribed Image Text:In class, students were given the following problem:
"Aluminum satellite dishes resist corrosion because aluminum reacts with oxygen gas (0₂) to form a
coating of aluminum oxide (Al2O3) according to the following chemical equation:
4Al(s) + 302(g) →2A/203(s)
What is the mass of 9.45 moles of Al 203?
After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion:
1 mole AL, Q
9.45 moles Al₂O3× 102.2 grams of Al, 0,
Is this answer correct?
= 0.0926 grams of Al2O3
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