Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
a.) But-1-ene
b.) But-2-ene
c.) But-3-ene
d.) But-4-ene
![**Question:**
What is the major product of the following reaction?
**Reaction:**
\[ \text{CH}_3\text{CH}_2\text{CHBrCH}_3 \]
Reacts with:
- \[\text{CH}_3\text{CH}_2\text{O}^− \, \text{Na}^+\]
In the presence of:
- \[\text{CH}_3\text{CH}_2\text{OH}\]
**Explanation:**
This is an elimination reaction where 2-bromobutane reacts with sodium ethoxide (\[\text{CH}_3\text{CH}_2\text{O}^− \, \text{Na}^+\]) in ethanol (\[\text{CH}_3\text{CH}_2\text{OH}\]). The sodium ethoxide acts as a base, abstracting a proton from the neighboring carbon atom, leading to the elimination of hydrogen bromide (HBr) and the formation of an alkene, primarily 2-butene.
Because sodium ethoxide is a strong base, the major product is the more substituted alkene due to Zaitsev's rule, favoring the formation of 2-butene over 1-butene.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fed91e52e-2628-473e-a869-c97403a6fdd1%2Ff05dc595-d988-46f1-886c-ba3b8976aca0%2F5bx0toe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
What is the major product of the following reaction?
**Reaction:**
\[ \text{CH}_3\text{CH}_2\text{CHBrCH}_3 \]
Reacts with:
- \[\text{CH}_3\text{CH}_2\text{O}^− \, \text{Na}^+\]
In the presence of:
- \[\text{CH}_3\text{CH}_2\text{OH}\]
**Explanation:**
This is an elimination reaction where 2-bromobutane reacts with sodium ethoxide (\[\text{CH}_3\text{CH}_2\text{O}^− \, \text{Na}^+\]) in ethanol (\[\text{CH}_3\text{CH}_2\text{OH}\]). The sodium ethoxide acts as a base, abstracting a proton from the neighboring carbon atom, leading to the elimination of hydrogen bromide (HBr) and the formation of an alkene, primarily 2-butene.
Because sodium ethoxide is a strong base, the major product is the more substituted alkene due to Zaitsev's rule, favoring the formation of 2-butene over 1-butene.
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