What is the major organic product of the fallowing reaction? 1) 9-BBN, THF 2) H2O2, KOH, H,O [9-BBN is a borane derivative that has only one reactive B-H bond. It reacts just like BH3-THF) ОН HO H. Но H.
What is the major organic product of the fallowing reaction? 1) 9-BBN, THF 2) H2O2, KOH, H,O [9-BBN is a borane derivative that has only one reactive B-H bond. It reacts just like BH3-THF) ОН HO H. Но H.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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This is a question from a study guide for o-chem. If you can please go though the difference between a major and minor product and help me break down the reaction a bit id really appreciate it.
![**Question:**
What is the major organic product of the following reaction?
**Reaction Conditions:**
1) 9-BBN, THF
2) H₂O₂, KOH, H₂O
*[9-BBN is a borane derivative that has only one reactive B-H bond. It reacts just like BH₃•THF]*
**Reaction Scheme:**
A terminal alkyne is given, followed by an arrow indicating the application of the reaction conditions.
**Options for the Major Organic Product:**
1. **Structure 1:**
- A ketone with phenyl and isopropyl groups.
2. **Structure 2:**
- An alcohol with an internal double bond and hydroxyl groups on the alkene carbons.
3. **Structure 3:**
- An alcohol with the hydroxyl group attached to the end carbon of the alkyne chain (tautomerization possible).
4. **Structure 4:**
- A ketone with an isopropyl group and phenyl group directly attached to different carbons.
**Explanation of Graphs/Diagrams:**
- The reaction involves hydroboration-oxidation of the terminal alkyne. 9-BBN (9-borabicyclo[3.3.1]nonane) is used as the hydroboration reagent which adds across the triple bond.
- The subsequent oxidation step uses hydrogen peroxide in the presence of a base (KOH) to transform the boron into a hydroxyl group.
- The expected product is an anti-Markovnikov alcohol which may tautomerize to form an aldehyde or ketone under certain conditions.
For educational purposes, it's crucial to note that 9-BBN is selective and typically gives regioselective addition across unsaturated systems, resulting in the formation of alcohols from alkynes.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F44c34136-e117-491b-b58f-d0d94a4d60dd%2F6a8647ef-0a82-4277-91dc-06a0c1987768%2Flmo19sr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
What is the major organic product of the following reaction?
**Reaction Conditions:**
1) 9-BBN, THF
2) H₂O₂, KOH, H₂O
*[9-BBN is a borane derivative that has only one reactive B-H bond. It reacts just like BH₃•THF]*
**Reaction Scheme:**
A terminal alkyne is given, followed by an arrow indicating the application of the reaction conditions.
**Options for the Major Organic Product:**
1. **Structure 1:**
- A ketone with phenyl and isopropyl groups.
2. **Structure 2:**
- An alcohol with an internal double bond and hydroxyl groups on the alkene carbons.
3. **Structure 3:**
- An alcohol with the hydroxyl group attached to the end carbon of the alkyne chain (tautomerization possible).
4. **Structure 4:**
- A ketone with an isopropyl group and phenyl group directly attached to different carbons.
**Explanation of Graphs/Diagrams:**
- The reaction involves hydroboration-oxidation of the terminal alkyne. 9-BBN (9-borabicyclo[3.3.1]nonane) is used as the hydroboration reagent which adds across the triple bond.
- The subsequent oxidation step uses hydrogen peroxide in the presence of a base (KOH) to transform the boron into a hydroxyl group.
- The expected product is an anti-Markovnikov alcohol which may tautomerize to form an aldehyde or ketone under certain conditions.
For educational purposes, it's crucial to note that 9-BBN is selective and typically gives regioselective addition across unsaturated systems, resulting in the formation of alcohols from alkynes.
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