What is the magnitude of the acceleration of gravity on a planet where a space explorer's 50.0 cm long pendulum oscillates 120. cycles in 280. s?(In the two image is a possible formula) Determining Gravitational AccelerationA physics student discovers from his studies that he can determine theacceleration of gravity at his location using just a pendulum and a digitaltimer. He carefully measures the period of his 0.750 m pendulum 20 timesand calculates an average period of 1.739 s. (a) What is gravitationalacceleration at his location? (b) Based on what you know about the acceptedvalue of g near the earth's surface, what could you deduce about thestudent's location relative to sea level?Periodic Motion273Solution:a. Rearrange Equation 12.9 to solve for the magnitude of g:T= 2T g|4T4T (0.750 m)g =(1.739 s)g = 9.790 m/s? = 9.79 m/sb. You know that gravitational acceleration decreases with distance fromthe center of the earth. Therefore, assuming his measurements are accurate,you can deduce that the student lives at a high elevation, perhaps in amountainous region, since his value of g| is less than the accepted sea-level value of 9.81 m/s. EXAMPLE 12-5Analyzing WavesFigure 12-27a shows a wave graph, and Figure 12-27b shows a vibrationgraph for the same wave. Find the wave's (a) amplitude (A), (b) wavelength(A), (c) frequency (f). (d) period (T), and (e) speed (v).Solution:a. Amplitude:A = 2(dpeak - duough) = [(+10 cm)-(-10 cm)]A = 10 cm%3Db. Wavelength: A = 20 cm (from Figure 12-27a)c. Frequency:f%3Dn cycles 1 cycleAt2s(from Figure 12-27b)%3Df = 0.5 sd. Period:T= 1/f=0.5 s%3DT 2 se. Speed:v = Af (0.2 m)(0.5 s)v 0.1 m/s

Name: What is the magnitude of the acceleration of gravity on a planet where
Uploaded: 2024-03-20T06:58:04.000Z
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Description: What is the magnitude of the acceleration of gravity on a planet where a space explorer's 50.0 cm long pendulum oscillates 120. cycles in 280. s?(In the two image is a possible formula) Determining Gravitational AccelerationA physics student discover