What is the magnetic field at point P shown below if a=3.39mm, b = 6.81mm, and the current 1=5,075A? Define positive as out of the page. Assume 3 significant digits and units of Tesla. b PI -a- 1
What is the magnetic field at point P shown below if a=3.39mm, b = 6.81mm, and the current 1=5,075A? Define positive as out of the page. Assume 3 significant digits and units of Tesla. b PI -a- 1
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![What is the magnetic field at point P shown below if
a=3.39mm, b = 6.81mm, and the current 1=5,075A?
Define positive as out of the page. Assume 3 significant
digits and units of Tesla.
b
Pl
—a—](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3200e892-7b83-4670-8aa5-c4c84f2a6adb%2F93aaed96-fb7f-404b-a765-4d256b6f8e97%2Fnq2migc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:What is the magnetic field at point P shown below if
a=3.39mm, b = 6.81mm, and the current 1=5,075A?
Define positive as out of the page. Assume 3 significant
digits and units of Tesla.
b
Pl
—a—
![The straight line segments do not
contribute to B(P) since the currents are
pointed directly towards (or away from) the
point P. So we only have to worry about the
arc shaped elements "a" and "b".
You know that the value at the center of a
μοι
loop is B = HT. In this case each arc
2r
represents 1/4 of a loop, so the contribution
μοι
will be B =
8r
According to the RHR, the contribution from
arc "a" is positive while the contribution from
arc "b" is negative.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3200e892-7b83-4670-8aa5-c4c84f2a6adb%2F93aaed96-fb7f-404b-a765-4d256b6f8e97%2Fn35bvi5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The straight line segments do not
contribute to B(P) since the currents are
pointed directly towards (or away from) the
point P. So we only have to worry about the
arc shaped elements "a" and "b".
You know that the value at the center of a
μοι
loop is B = HT. In this case each arc
2r
represents 1/4 of a loop, so the contribution
μοι
will be B =
8r
According to the RHR, the contribution from
arc "a" is positive while the contribution from
arc "b" is negative.
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