What is the length of the polar curve r = 7 sin 0 from 0 = 0 to 0 = 2n? Enter a numerical value only, round your answer to one decimal place.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Description:**

What is the length of the polar curve \( r = 7 \sin \theta \) from \( \theta = 0 \) to \( \theta = 2\pi \)?

*Note: Enter a numerical value only, rounding your answer to one decimal place.*

**Explanation:**

This problem asks for the length of a polar curve defined by the equation \( r = 7 \sin \theta \). The range of \(\theta\) is from 0 to \(2\pi\). This is a mathematical problem involving integration to calculate the arc length of the curve in polar coordinates. To solve this, one would use the formula for the arc length of a polar curve:

\[
L = \int_a^b \sqrt{\left(\frac{dr}{d\theta}\right)^2 + r^2} \, d\theta
\]

Where \( r = 7 \sin \theta \) and the limits of integration are \( a = 0 \) and \( b = 2\pi \). 

To find the solution, you will need to:

1. Compute \(\frac{dr}{d\theta}\).
2. Substitute \( r \) and \(\frac{dr}{d\theta}\) into the arc length formula.
3. Evaluate the integral for \(\theta\) ranging from 0 to \(2\pi\).
4. Round the result to one decimal place.
Transcribed Image Text:**Problem Description:** What is the length of the polar curve \( r = 7 \sin \theta \) from \( \theta = 0 \) to \( \theta = 2\pi \)? *Note: Enter a numerical value only, rounding your answer to one decimal place.* **Explanation:** This problem asks for the length of a polar curve defined by the equation \( r = 7 \sin \theta \). The range of \(\theta\) is from 0 to \(2\pi\). This is a mathematical problem involving integration to calculate the arc length of the curve in polar coordinates. To solve this, one would use the formula for the arc length of a polar curve: \[ L = \int_a^b \sqrt{\left(\frac{dr}{d\theta}\right)^2 + r^2} \, d\theta \] Where \( r = 7 \sin \theta \) and the limits of integration are \( a = 0 \) and \( b = 2\pi \). To find the solution, you will need to: 1. Compute \(\frac{dr}{d\theta}\). 2. Substitute \( r \) and \(\frac{dr}{d\theta}\) into the arc length formula. 3. Evaluate the integral for \(\theta\) ranging from 0 to \(2\pi\). 4. Round the result to one decimal place.
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