What is the inverse of ƒ (x) = (2x + 1)² for x ≥ − 1/1/? ƒ−¹(x) = − ¹⁄/ (√x + 1) - for x ≥ 1/1/20 X (1 + x^² ) ² − = (x) ₁_ƒ° for x > 0 루 (1 - x^² ) ² = (x) ₁_ƒ ° for x ≥ 0 ƒ−¹(x) = ½ / (√x − 1) for x ≥ 1/1/1

Q: find the inverse of

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A: The solution are next step

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