What is the inner radius of the spherical conductor?
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Q: QUESTION 32 In a version of Millikan's experiment, an oil droplet is released and when it has…
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- At points P & Q, what is the direction and magnitude of the electric field?Suppose we have a charge, q1=3 μC. This charge makes an electric field some distance r=69 cm away from it. Now suppose our measurement of q1 is only accurate to within 0.1 μC, and our measurement of r is only accurate to within 1 cm. a)If we were to calculate the electric field made by that charge at the indicated distance, what would be the uncertainty in our calculation due only to the uncertainty in the size of q1? b)What is the uncertainty in our field calculation due only to the uncertainty in the charge separation r? c)What is the total uncertainty in our electric field calculation due to the uncertainty in the size of q1 and the uncertainty in the charge separation r?The classic Millikan oil drop experiment was the first to obtain an accurate measurement of the charge on an electron. In it, oil drops w -e microscope Assume the oil drop to be 2.50 µm in radius and have a density of 942 kg/m3. (a) Find the weight of the drop. 2355 How is the mass of the spherical drop related to its volume and density? N (b) If the drop has a single excess electron, find the magnitude of the electric field strength needed to balance its weight. N/C
- The direction of the electric field shown in each part is that produced by the charge distribution in the wire. Justify the direction shown in each part, using the Coulomb force law and the definition of E = F/q, where q is a positive test charge.The voltage across a membrane forming a cell wall is 84 mV and the membrane is 7.5 nm thick. What is the electric field strength in the cell wall, in volts per meter?Parallel conducting plates create nearly uniform fields that are used to accelerate and direct beams of electrons. Typically we would free the electrons from a surface by heating it up. One way is to run a current through a wire with resistance. The power dissipated in the wire causes it to increase its temperature to the point that it can radiate that power away, mostly carried off as light. The hot electrons escape the potential barrier at the surface and are "free" to use. Consider a source of electrons that is small, like a tiny hot filament. The electrons are freed from the surface but the positive charge they leave behind holds them in a cloud near the filament. Now we add another plate at voltage VV some distance dd away. We put a little hole in that plate to enable the electrons to zip on through. The experiment looks something like this. While they seem antiquated, the concept is still useful. It is the basis of modern X-ray tubes, and until only a few years ago all…