What is the importance of setting an alpha level
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A: From the provided information, Standard deviation (σ) = 6 Z value = 1.25 And X = 48
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A: It is given asx̄ = 73.3s = 8
Q: The most common alpha level is 0.05. When is a higher alpha level (e.g. 0.10) typically used?
A: The common level of significance is .
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A: Solution
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A: Answer is 2.36
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A: From the provided information,Last year, 58% of butterflies in NC were monarchs.
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Q: A. CONSIDER that the data is CORRELATED use alpha .05. Provide the following: 1. Number of…
A: Red Orange Yellow Green Blue 43 39 38 33 31 39 43 39 35 34 41 44 42 34 32 42 35 39 37 32…
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A: (b) The probability of X lies between 2 and 2.6 is, Therefore, the required probability is, 0.30
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Q: The article cited in Exercise 4 also investigated the effects of the factors on glucose consumption…
A: Hey there! Thank you for posting the question. Since your question has more than 3 parts, we are…
Q: Question two Taken directly from the unit notes. A researcher is proposing that exercise makes a…
A: Given: Average hours of sleep needed(X) 4 5.2 2 3.4 8 10 1.5 6 Hours of exercise(Y) 8.6 8.1 9…
Q: I want to explain these outputs in detail
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Q: What does am/n mean ?
A: Let the given expression be y -y = amnThis means that, power to the a is in fraction which can be…
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- A diabetic person is interested in determining how the amount of aerobic exercise impacts his blood sugar. When blood sugar reaches 170 mg/dl, he goes out for a run at a pace of 10 minutes per mile. On different days, he runs different distances and measures his blood sugar after completing his run. The preferred blood sugar level is in the range of 80 to120 mg/dl. Levels that are too low or too high are extremely dangerous. The data generated are given in the following table: Distance (miles),x Blood sugar(mg/dl gram),y 2 136 2 146 2.5 131 2.5 125 3 120 3 116 3.5 104 3.5 95 4 85 4 94 4.5 83 4.5 75 Based on the scenario above, analyse the data with appropriate statistical methods and describe your findings in details. Use alpha=0.05 [note: use hypothesis, test statistics confidence interval etc.] ]How do we set an "alpha level" in science? How is this related to our comparison with a "p-value"?Radon is a gas emitted from the ground that can collect in houses in buildings. At certain levels it can cause lung cancer. Radon concentrations are measured in picocuries per liter (pCi/L). A radon level of 4 pCi/L is considered “acceptable” Radon levels in a house vary from week to week. In one house, a sample of 6 weeks had the following readings for radon level (in pCi/L): 1.9 2.8 3.9 3.9 4.2 5.7 Find the variance and standard deviation (definitional formula). Show your work using a table.
- The well-known psychologist Dr. Elbod has established what he calls his Generalized Anxiety Scale (GAS). The GAS, which is a scale from o to 10, measures the "general anxiety" of an individual, with higher GAS scores corresponding to more anxiety. (Dr. Elbod's assessment of anxiety is based on a variety of measurements, both physiological and psychological.) 圖 Aa We're interested in making predictions about individuals' sleep behavior based on their GAS scores. The bivariate data below give the GAS score (denoted by x) and the number of hours of sleep last night (denoted by y ) for each of the fifteen adults in a study. The least-squares regression line for these data has equation =8.36 – 0.25.x. This line, along with a scatter plot of the sample data, is shown in Figure 1.A researcher develops a test for identifying intellectually gifted children. It has a μ=56 and σ=8. a. what percentage of children are expected to score above 60? b. What percentage of the scores will be below 54? *ANSWER BOTH PARTS A & B*Use the provided information to calculate the t statistic and critical t values.
- Dr.Blume has trained observers to use frequency recording to record the behavior of 12 schizophrenic clients. According to the analysis of the data κ = 0 . 47, do you think the observers are sufficiently trained to allow Dr. Blume to proceed with the research?Please review Section 11.1. Are you an impulse shopper? A survey of 500 grocery shoppers indicated that 16% of males and 42% of females make an impulse purchase every time they shop. Assume that the survey consisted of 250 males and 250 females. Let group 1 be the males and let group 2 be the females.alpha = 0.05H0: pie = pieH1: pie not = pie Calculate the test statistic: (Round to three decimal places as needed.)Determine the critical value: (Round to three decimal places as needed.)State the Conclusion:Alpha is usually set at .05 but it does not have to be; this is the decision of the statistician. Alpha is usually set at .05 but it does not have to be; this is the decision of the statistician. True False
- A study was conducted at a local college to analyze the average cumulative GPA of students who graduated last year. Which of these terms is used to refer to: the average cumulative GPA of students in the study who graduated from the college last year?A psychologist believes that the age of an adolescent will have an impact on the number of phone calls made to the opposite sex (in heterosexual people) over the course of one month. They also suspect that gender of the adolescent will have an impact on the number of phone calls made to the opposite sex. Using the hypothetical data provided below, run your analyses in R to test whether age and gender impacts the number of phone calls an adolescent makes. Gender (Binary) Girl Boy Age Young Adolescents (11-14) 7, 2, 3, 5, 3 1, 2, 3, 2, 1 Older Adolescents (15-18) 15, 26, 19, 21, 18 10, 8, 5, 16, 9 ( What kind of statistical analysis do you need to use and why? State the null and alternative hypotheses. Check your assumptions. Include screenshots of your R output and explain why each of them are or are not met. Using R, run your analysis and include a screenshot. Using R, run post-hoc tests and include a screenshot. What do you…he General Social Survey asked the question, "After an average work day, about how many hours do you have to relax or pursue activities that you enjoy?" to a random sample of 1,155 Americans. The average relaxing time was found to be 1.65 hours. G. What is D. What is the statistic given? Describe it in words and give the numerical value. E. Describe the parameter corresponding to the statistic from Part (D) in words.