What is the ideal speed to take a 103-m-radius curve banked at a 18° angle? Assume the car is moving in a horizontal circle at uniform speed. V= m/s Banked curve

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Chapter1: Units, Trigonometry. And Vectors
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**Banked Curve Problem**

**Question:**
What is the ideal speed to take a 103-meter radius curve banked at a 18° angle? Assume the car is moving in a horizontal circle at uniform speed.

**Diagram Explanation:**
The image shows a car taking a banked curve. The curve is inclined at an 18° angle, creating a scenario where the centripetal force and gravitational force work together to help the car maintain its path without skidding.

**Formula to Use:**
To solve for the ideal speed (\( v \)), use the formula for the banked curve:
\[ 
v = \sqrt{r \cdot g \cdot \tan(\theta)} 
\]
where:
- \( r \) is the radius of the curve (103 meters)
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \))
- \( \theta \) is the banking angle (18°)

**Calculation Needed:**
Substitute the given values into the formula to find the speed in meters per second (m/s).
Transcribed Image Text:**Banked Curve Problem** **Question:** What is the ideal speed to take a 103-meter radius curve banked at a 18° angle? Assume the car is moving in a horizontal circle at uniform speed. **Diagram Explanation:** The image shows a car taking a banked curve. The curve is inclined at an 18° angle, creating a scenario where the centripetal force and gravitational force work together to help the car maintain its path without skidding. **Formula to Use:** To solve for the ideal speed (\( v \)), use the formula for the banked curve: \[ v = \sqrt{r \cdot g \cdot \tan(\theta)} \] where: - \( r \) is the radius of the curve (103 meters) - \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)) - \( \theta \) is the banking angle (18°) **Calculation Needed:** Substitute the given values into the formula to find the speed in meters per second (m/s).
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