What is the hybridization for the carbon with the arrow in the diagram below? CH3 H₂C H₂C H3C C 생 A) sp³ B) sp² ΤΟ CH3 CH CH C C. OH CH CH C. с CH H₂C H₂ CH₂ CH3 CH₂

Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Determining Carbon Hybridization in a Molecule**

**Question:**
What is the hybridization for the **carbon** with the arrow in the diagram below?

**Diagram Explanation:**
The diagram shows a complex organic molecule with multiple carbon (C) atoms, hydrogen (H) atoms, and one oxygen (O) atom. These atoms are connected through single and double bonds:
- The carbon with an arrow pointing to it (highlighted for hybridization analysis) is bonded to:
  - An OH group via a single bond.
  - Another carbon via a double bond (indicating sp² hybridization).
  - Structurally, it sits within a larger ring structure, contributing to multiple benzene-like ring systems.

**Answer Options:**
A) \( sp^3 \)
B) \( sp^2 \)
C) \( sp \)
D) \( sp^4 \)
E) That carbon cannot be described by valence bond theory/hybrid orbitals.

From the diagram, it is evident that the carbon atom in question forms three sigma bonds (one with an OH group, one with a neighboring carbon, and participates in a double bond with another carbon) and one pi bond (double bond with a carbon), suggesting an **\( sp^2 \) hybridization.

**Correct Answer:**
B) \( sp^2 \)
Transcribed Image Text:**Determining Carbon Hybridization in a Molecule** **Question:** What is the hybridization for the **carbon** with the arrow in the diagram below? **Diagram Explanation:** The diagram shows a complex organic molecule with multiple carbon (C) atoms, hydrogen (H) atoms, and one oxygen (O) atom. These atoms are connected through single and double bonds: - The carbon with an arrow pointing to it (highlighted for hybridization analysis) is bonded to: - An OH group via a single bond. - Another carbon via a double bond (indicating sp² hybridization). - Structurally, it sits within a larger ring structure, contributing to multiple benzene-like ring systems. **Answer Options:** A) \( sp^3 \) B) \( sp^2 \) C) \( sp \) D) \( sp^4 \) E) That carbon cannot be described by valence bond theory/hybrid orbitals. From the diagram, it is evident that the carbon atom in question forms three sigma bonds (one with an OH group, one with a neighboring carbon, and participates in a double bond with another carbon) and one pi bond (double bond with a carbon), suggesting an **\( sp^2 \) hybridization. **Correct Answer:** B) \( sp^2 \)
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