What is the half-life of a first-order reaction with a rate constant of 8.90x10¬4 s-1? Express your answer with the appropriate units. • View Available Hint(s) Tempjates Symbols undo redo reset keyboard shortcuts help Value Units
What is the half-life of a first-order reaction with a rate constant of 8.90x10¬4 s-1? Express your answer with the appropriate units. • View Available Hint(s) Tempjates Symbols undo redo reset keyboard shortcuts help Value Units
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The integrated rate law allows chemists to predict the reactant concentration after a certain amount of
time, or the time it would take for a certain concentration to be reached.
The integrated rate law for a first-order reaction is:
Half-life equation for first-order reactions:
0.693
t1/2 =
[A] = [A]oe-kt
where t/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds (s).
Now say we are particularly interested in the time it would take for the concentration to become one-
[A],
half of its initial value. Then we could substitute " for [A] and rearrange the equation to:
0.693
t1/2
This equation calculates the time required for the reactant concentration to drop to half its initial value.
In other words, it calculates the half-life.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F65639ce4-957e-4e3f-ad7d-82256b02ea7d%2F68176758-fef6-4a28-953f-e5631ba75195%2Falarl3f_processed.png&w=3840&q=75)
Transcribed Image Text:The integrated rate law allows chemists to predict the reactant concentration after a certain amount of
time, or the time it would take for a certain concentration to be reached.
The integrated rate law for a first-order reaction is:
Half-life equation for first-order reactions:
0.693
t1/2 =
[A] = [A]oe-kt
where t/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds (s).
Now say we are particularly interested in the time it would take for the concentration to become one-
[A],
half of its initial value. Then we could substitute " for [A] and rearrange the equation to:
0.693
t1/2
This equation calculates the time required for the reactant concentration to drop to half its initial value.
In other words, it calculates the half-life.

Transcribed Image Text:What is the half-life of a first-order reaction with a rate constant of 8.90x104 s-1?
Express your answer with the appropriate units.
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