What is the general solution to the equation? 2 sin² x + 5 sin x-3=0 Drag solutions to the box to correctly complete the table. General solution to 2 sin² x + 5 sin x − 3 = 0 0 = 2 + 2πn, where n is an integer 0 = + πn, where n is an integer 0 = 0 = 5π 6 + 2πn, where n is an integer +2πn, where n is an integer 0 - Ꮎ = πn, where n is an integer 11″ + 2πn, where n is an integer

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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What is the general solution to the equation?

2sin2x+5sinx−3=0

Drag solutions to the box to correctly complete the table.

What is the general solution to the equation?
2 sin²x + 5 sin x - 3 0
Drag solutions to the box to correctly complete the table.
0 =
2π
General solution to 2 sin² x + 5 sin x
+ 2πn, where n is an integer
+лn, where n is an integer
0
=
5π
6
3=0
+ 2πn, where n is an integer
+2πn, where n is an integer
0
0 = πn, where n is an integer
11πT
6
+ 2πn, where n is an integer
Transcribed Image Text:What is the general solution to the equation? 2 sin²x + 5 sin x - 3 0 Drag solutions to the box to correctly complete the table. 0 = 2π General solution to 2 sin² x + 5 sin x + 2πn, where n is an integer +лn, where n is an integer 0 = 5π 6 3=0 + 2πn, where n is an integer +2πn, where n is an integer 0 0 = πn, where n is an integer 11πT 6 + 2πn, where n is an integer
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