What is the general solution of (D² – 2D + 5) y = 0 ? - y = Cie + C2e3 %3D y = Cie cos 2x + C2e sin 2x %3D Oy = C1 cos 2x + C2 sin 2x y = Cie cos 4x + C2e" sin 4x %3D
What is the general solution of (D² – 2D + 5) y = 0 ? - y = Cie + C2e3 %3D y = Cie cos 2x + C2e sin 2x %3D Oy = C1 cos 2x + C2 sin 2x y = Cie cos 4x + C2e" sin 4x %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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what is the answer between the choices
Transcribed Image Text:What is the general solution of (D² – 2D + 5) y = 0 ?
%3D
y = Cie + C2e
y = Cie" cos 2x + Cze" sin 2x
Oy = Ci cos 2x + C2 sin 2x
Oy = Cie* cos 4x + C2e" sin 4x
%3D
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