What is the experimental molar mass (that is, calculated from the data given and not taken from the periodic table) of magnesium if 0.0181 grams of magnesium generates 18.53 mL of hydrogen at 23.3 °C with a hydrogen partial pressure of 742.0 torr? Note that the partial pressure of water vapor has already been subtracted from the total pressure. 26.2 g/mol 23.8 g/mol 21.0 g/mol 24.3 g/mol 26.0 g/mol
What is the experimental molar mass (that is, calculated from the data given and not taken from the periodic table) of magnesium if 0.0181 grams of magnesium generates 18.53 mL of hydrogen at 23.3 °C with a hydrogen partial pressure of 742.0 torr? Note that the partial pressure of water vapor has already been subtracted from the total pressure. 26.2 g/mol 23.8 g/mol 21.0 g/mol 24.3 g/mol 26.0 g/mol
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Chapter1: Chemical Foundations
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What is the experimental molar mass (that is, calculated from the data given and not taken from the periodic table) of magnesium if 0.0181 grams of magnesium generates 18.53 mL of hydrogen at 23.3 °C with a hydrogen partial pressure of 742.0 torr? Note that the partial pressure of water vapor has already been subtracted from the total pressure.26.2 g/mol23.8 g/mol21.0 g/mol24.3 g/mol26.0 g/mol
Expert Solution
Step 1
Given :
Mass of Mg = 0.0181 g
Volume of hydrogen = 18.53 ml
Temperature = 23.3 °C
Partial pressure of hydrogen = 742 torr
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