What is the expected major product resulting from treatment of (E)-3-methyl-3-hexene with Brz in the presence of methanol, CH3OH? Br Br OCH3 OCH3 OCH3 H,CO Br Br + enantiomer + enantiomer + enantiomer + enantiomer II IV II IV All of the above are produced in equal amounts

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**Question:**  
What is the expected major product resulting from the treatment of (E)-3-methyl-3-hexene with \(Br_2\) in the presence of methanol, \(CH_3OH\)?

**Chemical Structures with Enantiomers:**

- **Structure I:**
  ![Structure I](https://via.placeholder.com/100)  
  \[\text{CH}_3-\text{CH}(Br)-\text{CH}(\text{OCH}_3)-\text{CH}_2-\text{CH}_3\]
  + enantiomer

- **Structure II:**
  ![Structure II](https://via.placeholder.com/100)  
  \[\text{CH}_3-\text{CH}(Br)-\text{CH}(\text{OCH}_3)-\text{CH}_2-\text{CH}_3\]
  + enantiomer

- **Structure III:**
  ![Structure III](https://via.placeholder.com/100)  
  \[\text{CH}_3-\text{CH}(\text{OCH}_3)-\text{CH}(Br)-\text{CH}_2-\text{CH}_2-\text{CH}_3\]
  + enantiomer

- **Structure IV:**
  ![Structure IV](https://via.placeholder.com/100)  
  \[\text{CH}_3-\text{CH}(\text{OCH}_3)-\text{CH}(Br)-\text{CH}_2-\text{CH}_2-\text{CH}_3\]
  + enantiomer

**Choices:**
- **A.** I
- **B.** II
- **C.** III
- **D.** IV
- **E.** All of the above are produced in equal amounts

**Explanation:**

When (E)-3-methyl-3-hexene is treated with \(Br_2\) in the presence of methanol \((CH_3OH)\), the methanol acts as a nucleophile, leading to the formation of bromomethoxy products. The reaction typically results in the formation of major products represented by structures I, II, III, and IV, each existing along with its respective enantiomer.

In the answer choices, students are tasked with determining which one of these structures (or combinations
Transcribed Image Text:**Question:** What is the expected major product resulting from the treatment of (E)-3-methyl-3-hexene with \(Br_2\) in the presence of methanol, \(CH_3OH\)? **Chemical Structures with Enantiomers:** - **Structure I:** ![Structure I](https://via.placeholder.com/100) \[\text{CH}_3-\text{CH}(Br)-\text{CH}(\text{OCH}_3)-\text{CH}_2-\text{CH}_3\] + enantiomer - **Structure II:** ![Structure II](https://via.placeholder.com/100) \[\text{CH}_3-\text{CH}(Br)-\text{CH}(\text{OCH}_3)-\text{CH}_2-\text{CH}_3\] + enantiomer - **Structure III:** ![Structure III](https://via.placeholder.com/100) \[\text{CH}_3-\text{CH}(\text{OCH}_3)-\text{CH}(Br)-\text{CH}_2-\text{CH}_2-\text{CH}_3\] + enantiomer - **Structure IV:** ![Structure IV](https://via.placeholder.com/100) \[\text{CH}_3-\text{CH}(\text{OCH}_3)-\text{CH}(Br)-\text{CH}_2-\text{CH}_2-\text{CH}_3\] + enantiomer **Choices:** - **A.** I - **B.** II - **C.** III - **D.** IV - **E.** All of the above are produced in equal amounts **Explanation:** When (E)-3-methyl-3-hexene is treated with \(Br_2\) in the presence of methanol \((CH_3OH)\), the methanol acts as a nucleophile, leading to the formation of bromomethoxy products. The reaction typically results in the formation of major products represented by structures I, II, III, and IV, each existing along with its respective enantiomer. In the answer choices, students are tasked with determining which one of these structures (or combinations
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