What is the error when using midpoints with 10 subintervals? (Do not round your answer.) hat is the ratio of the left-endpoint approximation error to the midpoint error? (Round your answer to two decimal places.) For 20 subintervals, find the ratio of the error using left endpoints to the midpoint error. How does this compare to your answer in part (b)? O The ratio is about the same as part (b). O The ratio is significantly larger than part (b). O The ratio is significantly smaller than part (b). hat about for 50 subintervals? The ratio is about the same as part (b). The ratio is significantly larger than part (b). The ratio is significantly smaller than part (b).
What is the error when using midpoints with 10 subintervals? (Do not round your answer.) hat is the ratio of the left-endpoint approximation error to the midpoint error? (Round your answer to two decimal places.) For 20 subintervals, find the ratio of the error using left endpoints to the midpoint error. How does this compare to your answer in part (b)? O The ratio is about the same as part (b). O The ratio is significantly larger than part (b). O The ratio is significantly smaller than part (b). hat about for 50 subintervals? The ratio is about the same as part (b). The ratio is significantly larger than part (b). The ratio is significantly smaller than part (b).
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 94E
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please very soon full explanation . fucntion y = 2 cos(x), and set the interval to [−4.02, 4.02].ONLY PART (B),(C)
![(a) With 10 rectangles using left endpoints, how many rectangles are contributing negative area values to the estimated net area?
How many are positive?
Is this the same as when using midpoints?
Yes
No
(b) What is the error when using midpoints with 10 subintervals? (Do not round your answer.)
What is the ratio of the left-endpoint approximation error to the midpoint error? (Round your answer to two decimal places.)
(c) For 20 subintervals, find the ratio of the error using left endpoints to the midpoint error. How does this compare to your answer in part (b)?
The ratio is about the same as part (b).
The ratio is significantly larger than part (b).
The ratio is significantly smaller than part (b).
What about for 50 subintervals?
The ratio is about the same as part (b).
The ratio is significantly larger than part (b).
The ratio is significantly smaller than part (b).
(d) Of the available choices, how many subintervals are required to give a midpoint approximation accurate to 2 decimal places?
(e) Estimate an interval that would give a true net area of 0.
[1.56, 3.14]
О 3.14, -1.57]
[О, 4.01]
[0, 3.14]
O (-4.01, 0]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3cb84e58-1f2e-4d77-87c0-828723dbdfe0%2F4f13507f-49ce-44bd-bb24-1bad29475199%2Fwo1cpe_processed.png&w=3840&q=75)
Transcribed Image Text:(a) With 10 rectangles using left endpoints, how many rectangles are contributing negative area values to the estimated net area?
How many are positive?
Is this the same as when using midpoints?
Yes
No
(b) What is the error when using midpoints with 10 subintervals? (Do not round your answer.)
What is the ratio of the left-endpoint approximation error to the midpoint error? (Round your answer to two decimal places.)
(c) For 20 subintervals, find the ratio of the error using left endpoints to the midpoint error. How does this compare to your answer in part (b)?
The ratio is about the same as part (b).
The ratio is significantly larger than part (b).
The ratio is significantly smaller than part (b).
What about for 50 subintervals?
The ratio is about the same as part (b).
The ratio is significantly larger than part (b).
The ratio is significantly smaller than part (b).
(d) Of the available choices, how many subintervals are required to give a midpoint approximation accurate to 2 decimal places?
(e) Estimate an interval that would give a true net area of 0.
[1.56, 3.14]
О 3.14, -1.57]
[О, 4.01]
[0, 3.14]
O (-4.01, 0]
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