What is the error analysis for an experimental capacitance with a result of -114.7µF and the theoretical capacitance with a result of 36µF
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What is the error analysis for an experimental capacitance with a result of -114.7µF and the theoretical capacitance with a result of 36µF
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- A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted between the plates without changing the spacing, and the capacitance becomes 15 F. What is the dielectric constant of this material?A 10-9.F capacitor (1 nanofarad) is charged to 50 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 3× 1018 2, on a humid day, the resistance is 6 × 10° 2. How long will it take the capacitor voltage to dissipate to half its original value on each day? ... On the dry day, it will take seconds.An initially uncharged parallel plate capacitor is connected to a circuit containing a battery with emf -15V and a resistor, R = 8.5MN as shown in the figure to below. The capacitor whose plates have an area of A = 3.1mm² are separated by a distance of d = 3.4mm and one third of the capacitor is filled with a dielectric material, K₁= 1.1 and the rest (two thirds) is filled with another dielectric material, K₂=4.5. At t=0 the switch is closed. 7.1 seconds after the switch is closed the electric field within the first dielectric material (₁) is observed to be 15 x 10³ N/C. Find the potential difference across the capacitor at this instant (t = 7.1 s) in terms of permitivity of free space €0? Express your answer using zero decimal place. R S K₁ K₂
- Explain the relation between area, distance and capacitance RC CircuitsNumber 13 and 14a. Show how you would connect all five capacitors to get a maximum capacitance and find the maximum capacitance in terms of C. b. Show how you would connect all five capacitors to get a minimum capacitance and find the minimum capacitance in terms of C.
- A parallel-plate capacitor has plates of area 124.0 cm² and a separation of 1.00 cm. A battery charges the plates to a potential difference of 121.0 Vand is then disconnected. A dielectric slab of thickness 4.60 mm and dielectric constant 6.40 is then placed symmetrically between the plates. Find the capacitance before the slab is inserted. 1.098Complete SoluitonWith solution for study and comprehension TYSM!
- A 40 micro-farad capacitor is connected in series with a 40 ohm resistor. If the voltage is220-V, what is the current?An initially uncharged parallel plate capacitor is connected to a circuit containing a battery with emf-28V and a resistor, R = 8.4M as shown in the figure to below. The capacitor whose plates have an area of A= 4.2mm² are separated by a distance of d = 5.9mm and one third of the capacitor is filled with a dielectric material, K₁=1.8 and the rest (two thirds) is filled with another dielectric material, ₂-4.3. At t-0 the switch is closed. 2.7 seconds after the switch is closed the electric field within the first dielectric material (₁) is observed to be 10 x 10 N/C. Find the charge on the capacitor at this instant (t-2.7s) in terms of permitivity of free space €0? Express your answer using zero decimal place. R Answer:quick please