What is the equivalent capacitance between nodes a and b? a. 3 mF 6 mF O 4.5 mF O 9.0 mF O 7.5 mF O 2.0 mF
What is the equivalent capacitance between nodes a and b? a. 3 mF 6 mF O 4.5 mF O 9.0 mF O 7.5 mF O 2.0 mF
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Related questions
Question
Please answer correctly. Thank you
![**Problem Statement:**
What is the equivalent capacitance between nodes \( a \) and \( b \)?
**Diagram:**
The diagram shows two capacitors connected in parallel between two nodes, \( a \) and \( b \).
- The first capacitor has a capacitance of \( 3 \, \text{mF} \).
- The second capacitor has a capacitance of \( 6 \, \text{mF} \).
**Options:**
- \( 4.5 \, \text{mF} \)
- \( 9.0 \, \text{mF} \)
- \( 7.5 \, \text{mF} \)
- \( 2.0 \, \text{mF} \)
**Explanation:**
To find the equivalent capacitance \( C_{\text{eq}} \) for capacitors in parallel, use the formula:
\[ C_{\text{eq}} = C_1 + C_2 \]
Substituting the given values:
\[ C_{\text{eq}} = 3 \, \text{mF} + 6 \, \text{mF} = 9 \, \text{mF} \]
Thus, the equivalent capacitance between nodes \( a \) and \( b \) is \( 9.0 \, \text{mF} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd65464ea-20ac-437a-9b4f-902b3affc00d%2F1a994554-6308-47e5-9879-99794336edd5%2Fn04ms4s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
What is the equivalent capacitance between nodes \( a \) and \( b \)?
**Diagram:**
The diagram shows two capacitors connected in parallel between two nodes, \( a \) and \( b \).
- The first capacitor has a capacitance of \( 3 \, \text{mF} \).
- The second capacitor has a capacitance of \( 6 \, \text{mF} \).
**Options:**
- \( 4.5 \, \text{mF} \)
- \( 9.0 \, \text{mF} \)
- \( 7.5 \, \text{mF} \)
- \( 2.0 \, \text{mF} \)
**Explanation:**
To find the equivalent capacitance \( C_{\text{eq}} \) for capacitors in parallel, use the formula:
\[ C_{\text{eq}} = C_1 + C_2 \]
Substituting the given values:
\[ C_{\text{eq}} = 3 \, \text{mF} + 6 \, \text{mF} = 9 \, \text{mF} \]
Thus, the equivalent capacitance between nodes \( a \) and \( b \) is \( 9.0 \, \text{mF} \).
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,