What is the equation of the curve whose slope at any point is equal to y cot x + tan?x and which passes through (, 2) ? y = 3sin?x + 3 cos x у 3 cot x + V2 sec x A y = tan x + V2 sin x y = sec?x – 3cot²x Ов

Q: 2 1) F(u) = sin 2au (sintu+cosu)

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Q: Differentiate: y = sinh° (sin 5x) Oy' = 15 cos 5x sinh (sin 5x) cosh(sin 5x) Oy' = –15 sin 5x sinh?…

A: dsinh (ax)dx=a cosh (ax) dsin(ax)dx=a.cos(ax)

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Q: Equation: Answer:

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Q: 4. The 1" derivative of y : cotx a) xsec?x + tanx b) xsecx - tanx c) cot x + xcsc'x d) cot x - xcscx

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Q: Differentiate. ' a) y = 2cos(x²)

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Q: then A(-2u - 20) = -2 ---B 5 and Au 3 Au = 2 4

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Q: 5)find y y= Inl-decx +tanx)

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Q: If sin2x secx cotx = 3, find the value of csc x.

A: Given Equation:- sin2xsecxcotx=3