What is the equation of the curve that passes through the point (1, 3) and has a slope of 2 x+3 O 9 y = ( − 3x² + ½ x + 0.804) ³ O y = (2x² + 2x - 3.920) * O y = (2²1x² + 2/2 x − 0.804) ³ - ° y = (2x² + 2x - 3.920) 333 at any point (x, y)?

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter2: Functions And Graphs
Section2.4: Writing And Graphing Equations Of Lines
Problem 79E
Question

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What is the equation of the curve that passes through the point (1, 3) and has a slope of
2 x+3
√y
° y =
°
( − ²³/²x² + ²√x+0.804)
y =
y = (.
(3²2x² + 2/1 x − 3.920) 2/2
-
(2x² + 2x −0.804)
° y = ( ²1x² + 2x − 3.920) ³
-
at any point (x, y)?
Transcribed Image Text:What is the equation of the curve that passes through the point (1, 3) and has a slope of 2 x+3 √y ° y = ° ( − ²³/²x² + ²√x+0.804) y = y = (. (3²2x² + 2/1 x − 3.920) 2/2 - (2x² + 2x −0.804) ° y = ( ²1x² + 2x − 3.920) ³ - at any point (x, y)?
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