What is the equation of the circle that passes through points (2, 3), (6, 1), (4, –3)? x? – y? – 6x – 1= 0 32² + 3y? – 6x -1 = 0 Option 1 O Option 3 None of these 322 + 3y? – 6x +1=0 Option 5 O Option 4 x? + y? – 6x –1= 0 Option 2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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What is the equation of the circle that passes through points (2, 3), (6, 1), (4, –3)?
x? – y? – 6x – 1= 0
32² + 3y? – 6x -1 = 0
Option 1
O Option 3
None of these
322 + 3y? – 6x +1=0
Option 5
O Option 4
x? + y? – 6x –1= 0
Option 2
Transcribed Image Text:What is the equation of the circle that passes through points (2, 3), (6, 1), (4, –3)? x? – y? – 6x – 1= 0 32² + 3y? – 6x -1 = 0 Option 1 O Option 3 None of these 322 + 3y? – 6x +1=0 Option 5 O Option 4 x? + y? – 6x –1= 0 Option 2
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