What is the equation of the circle in standard form whose endpoints of a diameter are at A(-5,4) and B(3, - 2)? A(x+1)2+(y- 1)² = 25 B (x+3)2 +(y-2)² = 50 (x+4)2+(y- 3)² = 2 (x+5)2 + (y- 4)2 =100 %3D

College Algebra (MindTap Course List)
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Chapter7: Conic Sections And Quadratic Systems
Section7.CT: Chapter Test
Problem 4CT
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Question 3
What is the equation of the circle in standard form whose endpoints of a diameter
are at A(-5,4) and B(3,- 2)?
A (x+1)2 + (y- 1)2= 25
B (x+3)2 + (y- 2)² = 50
(x+4)2+(y- 3)² = 2
(x+5)2 + (y– 4)² = 100
Transcribed Image Text:Question 3 What is the equation of the circle in standard form whose endpoints of a diameter are at A(-5,4) and B(3,- 2)? A (x+1)2 + (y- 1)2= 25 B (x+3)2 + (y- 2)² = 50 (x+4)2+(y- 3)² = 2 (x+5)2 + (y– 4)² = 100
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