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What is the equation of a circle with a center of (6, -2) that has an area of 4n? (x – 6)² + (y + 2)² = 4 (2) (x - 6)2 + (y+ 2)² = 2 (3) (x + 6)² + (y – 2)² = 4 (4) (x + 6)2 + (y - 2)2 = 2

What is the equation of a circle with a center of (6, -2) that has an area of 4n? (x – 6)² + (y + 2)² = 4 (2) (x - 6)2 + (y+ 2)² = 2 (3) (x + 6)² + (y – 2)² = 4 (4) (x + 6)2 + (y - 2)2 = 2

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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What is the equation of a circle with a center of (6, -2) that has an area of 4n? (1) (x - 6)² + (y + 2)² = 4 (2) (x - 6)² + (y+ 2)² = 2 %3D (x + 6)² + (y – 2)2 = 2 %3D (3) (x + 6)² + (y - 2)² = 4 (4) %3D
Transcribed Image Text:What is the equation of a circle with a center of (6, -2) that has an area of 4n? (1) (x - 6)² + (y + 2)² = 4 (2) (x - 6)² + (y+ 2)² = 2 %3D (x + 6)² + (y – 2)2 = 2 %3D (3) (x + 6)² + (y - 2)² = 4 (4) %3D
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