What is the equation for the line perpendicular to the line represented by the equation y = x- 2 that passes through the point (4, –7)? O A. y =-3x – 2 о в. у3 -Зх- 5 O C. y = 3x + 2 о D. у3-3х + 5

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Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
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Question 18

### Problem Statement
What is the equation for the line perpendicular to the line represented by the equation \(y = \frac{1}{3}x - 2\) that passes through the point \((4, -7)\)?

### Multiple Choice Options
- **A.** \(y = -3x - 2\)
- **B.** \(y = -3x - 5\)
- **C.** \(y = 3x + 2\)
- **D.** \(y = -3x + 5\)

### Explanation
To solve this problem, you need to:
1. Determine the slope of the given line.
2. Find the slope of the line perpendicular to the given line.
3. Use the point-slope form to find the equation of the perpendicular line that passes through the given point.

#### Step-by-Step Solution
1. **Identify the slope of the given line:**
   The equation of the given line is \( y = \frac{1}{3}x - 2 \). The slope (\(m\)) is \(\frac{1}{3}\).

2. **Find the slope of the perpendicular line:**
   The slope of a line perpendicular to another line is the negative reciprocal of the original line's slope. 
   So, the slope \( m_{\text{perpendicular}} = -\frac{1}{(\frac{1}{3})} = -3 \).

3. **Use the point-slope form equation:**
   The point-slope form of a line's equation is \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \((x_1, y_1)\) is a point on the line. Here, \( m = -3 \) and the point is \( (4, -7) \).

   Plug the slope and the point into the point-slope form:
   \[
   y - (-7) = -3(x - 4)
   \]
   Simplify:
   \[
   y + 7 = -3x + 12
   \]
   \[
   y = -3x + 12 - 7
   \]
   \[
   y = -3x + 5
   \]

Therefore, the correct answer is:
- **D.** \(y = -3
Transcribed Image Text:### Problem Statement What is the equation for the line perpendicular to the line represented by the equation \(y = \frac{1}{3}x - 2\) that passes through the point \((4, -7)\)? ### Multiple Choice Options - **A.** \(y = -3x - 2\) - **B.** \(y = -3x - 5\) - **C.** \(y = 3x + 2\) - **D.** \(y = -3x + 5\) ### Explanation To solve this problem, you need to: 1. Determine the slope of the given line. 2. Find the slope of the line perpendicular to the given line. 3. Use the point-slope form to find the equation of the perpendicular line that passes through the given point. #### Step-by-Step Solution 1. **Identify the slope of the given line:** The equation of the given line is \( y = \frac{1}{3}x - 2 \). The slope (\(m\)) is \(\frac{1}{3}\). 2. **Find the slope of the perpendicular line:** The slope of a line perpendicular to another line is the negative reciprocal of the original line's slope. So, the slope \( m_{\text{perpendicular}} = -\frac{1}{(\frac{1}{3})} = -3 \). 3. **Use the point-slope form equation:** The point-slope form of a line's equation is \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \((x_1, y_1)\) is a point on the line. Here, \( m = -3 \) and the point is \( (4, -7) \). Plug the slope and the point into the point-slope form: \[ y - (-7) = -3(x - 4) \] Simplify: \[ y + 7 = -3x + 12 \] \[ y = -3x + 12 - 7 \] \[ y = -3x + 5 \] Therefore, the correct answer is: - **D.** \(y = -3
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