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What is the energy of a photon with a frequency of 8.40 x 1014 s¹? (h= 6.626 × 10-34 J·s)

What is the energy of a photon with a frequency of 8.40 x 1014 s¹? (h= 6.626 × 10-34 J·s)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question 12 of 65** **What is the energy of a photon with a frequency of \(8.40 \times 10^{14} \, \text{s}^{-1}\)? (h = \(6.626 \times 10^{-34} \, \text{J} \cdot \text{s}\))** This question asks you to calculate the energy of a photon given its frequency. The formula to use is: \[ E = h \cdot f \] Where: - \( E \) is the energy of the photon. - \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{J} \cdot \text{s}\)). - \( f \) is the frequency of the photon (\(8.40 \times 10^{14} \, \text{s}^{-1}\)). To solve the problem, multiply Planck’s constant by the frequency: \[ E = (6.626 \times 10^{-34} \, \text{J} \cdot \text{s}) \times (8.40 \times 10^{14} \, \text{s}^{-1}) \] Calculating this will give you the energy in joules.
Transcribed Image Text:**Question 12 of 65** **What is the energy of a photon with a frequency of \(8.40 \times 10^{14} \, \text{s}^{-1}\)? (h = \(6.626 \times 10^{-34} \, \text{J} \cdot \text{s}\))** This question asks you to calculate the energy of a photon given its frequency. The formula to use is: \[ E = h \cdot f \] Where: - \( E \) is the energy of the photon. - \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{J} \cdot \text{s}\)). - \( f \) is the frequency of the photon (\(8.40 \times 10^{14} \, \text{s}^{-1}\)). To solve the problem, multiply Planck’s constant by the frequency: \[ E = (6.626 \times 10^{-34} \, \text{J} \cdot \text{s}) \times (8.40 \times 10^{14} \, \text{s}^{-1}) \] Calculating this will give you the energy in joules.
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