What is the energy change when the temperature of 12.3 grams of gaseous helium is decreased from 37.7 °C to 22.9 °C ? Answer: Joules.

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Chapter1: Chemical Foundations
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**Problem Statement:**

What is the energy change when the temperature of 12.3 grams of gaseous helium is decreased from 37.7 °C to 22.9 °C?

**Answer:**

___ Joules.

**Instructions:**

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**Example Solution Process:**

1. Identify the initial and final temperatures of helium.
2. Use the specific heat capacity formula: 
   \[
   Q = mc\Delta T
   \]
   where:
   - \(Q\) is the heat energy change (in Joules),
   - \(m\) is the mass (in grams),
   - \(c\) is the specific heat capacity of helium (approximately 5.193 J/g°C),
   - \(\Delta T\) is the change in temperature (final - initial).
3. Calculate the change in temperature (\(\Delta T = 22.9 - 37.7\)).
4. Substitute the known values into the formula to find \(Q\).
Transcribed Image Text:**Problem Statement:** What is the energy change when the temperature of 12.3 grams of gaseous helium is decreased from 37.7 °C to 22.9 °C? **Answer:** ___ Joules. **Instructions:** - Provide your answer in the provided box. - Click "Submit Answer" to save your response. - If you wish to attempt another version of the problem, click "Try Another Version". - You have 3 item attempts remaining for this problem. **Example Solution Process:** 1. Identify the initial and final temperatures of helium. 2. Use the specific heat capacity formula: \[ Q = mc\Delta T \] where: - \(Q\) is the heat energy change (in Joules), - \(m\) is the mass (in grams), - \(c\) is the specific heat capacity of helium (approximately 5.193 J/g°C), - \(\Delta T\) is the change in temperature (final - initial). 3. Calculate the change in temperature (\(\Delta T = 22.9 - 37.7\)). 4. Substitute the known values into the formula to find \(Q\).
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