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"What is the end behavior for this equation? ƒ (x) = −3x² − 4x+7 -

"What is the end behavior for this equation? ƒ (x) = −3x² − 4x+7 -

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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What is the end behavior for this equation? f(x) = -3x² - 4x + 7 O As a →→→→∞0, f (x) - →→→∞, and as a →→∞, f (x) →→→∞ O As x→→→→∞, f (x) →→→∞, and as a →→∞, f (x) - O As x→→→→∞, f (x)→→∞, and as x→→→∞, f (x) →→∞ O As a →→∞, f (x) →→∞, and as a →→→∞, f (x) → →∞
Transcribed Image Text:What is the end behavior for this equation? f(x) = -3x² - 4x + 7 O As a →→→→∞0, f (x) - →→→∞, and as a →→∞, f (x) →→→∞ O As x→→→→∞, f (x) →→→∞, and as a →→∞, f (x) - O As x→→→→∞, f (x)→→∞, and as x→→→∞, f (x) →→∞ O As a →→∞, f (x) →→∞, and as a →→→∞, f (x) → →∞
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I understand that in standard form the value is -3, therefore, the parabola opens up negative and therefore the end behavior is negative. I do not understand how to get the middle two infinity parts. As I highlighted

As xx, f(x) →∞, and as a → ∞, f(x).
Transcribed Image Text:As xx, f(x) →∞, and as a → ∞, f(x).
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