What is the electrostatic force between a 1.6 x 10-19 C positive charge and a 3.4 x 1019 C negative charge that are separated by .02 m? Use 8.99 x 10° N m2 C2 as Coulomb's constant. Select one: 1.22 x 10-24 N O 1.22 x 10-28 N 1.36 x 1038 N 1.36 x 1042 N
What is the electrostatic force between a 1.6 x 10-19 C positive charge and a 3.4 x 1019 C negative charge that are separated by .02 m? Use 8.99 x 10° N m2 C2 as Coulomb's constant. Select one: 1.22 x 10-24 N O 1.22 x 10-28 N 1.36 x 1038 N 1.36 x 1042 N
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What is the electrostatic force between a 1.6 × 10^-19 C positive charge and a 3.4 × 10^-19 C negative charge that are separated by .02 m? Use 8.99 × 10^9 N m^2 C^-2 as Coulomb’s constant.
![### Question: Electrostatic Force Calculation
**Problem Statement:**
What is the electrostatic force between a \(1.6 \times 10^{-19}\) C positive charge and a \(3.4 \times 10^{-19}\) C negative charge that are separated by 0.02 m? Use \(8.99 \times 10^9\) N m² C⁻² as Coulomb's constant.
**Answer Choices:**
- **Option 1:** \( 1.22 \times 10^{-24} \, \text{N} \)
- **Option 2:** \( 1.22 \times 10^{-28} \, \text{N} \)
- **Option 3:** \( 1.36 \times 10^{38} \, \text{N} \)
- **Option 4:** \( 1.36 \times 10^{42} \, \text{N} \)
### Explanation:
To solve this problem, use Coulomb's Law, which is given by:
\[ F = k \frac{|q_1 q_2|}{r^2} \]
Where:
- \( F \) is the magnitude of the electrostatic force between the two charges.
- \( k \) is Coulomb's constant, \( 8.99 \times 10^9 \, \text{N m}^2 \text{C}^{-2} \).
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges.
- \( r \) is the separation between the charges.
Given:
- \( q_1 = 1.6 \times 10^{-19} \, \text{C} \)
- \( q_2 = 3.4 \times 10^{-19} \, \text{C} \)
- \( r = 0.02 \, \text{m} \)
Substitute the values into Coulomb's law:
\[ F = 8.99 \times 10^9 \times \frac{|(1.6 \times 10^{-19})(3.4 \times 10^{-19})|}{(0.02)^2} \]
\[ |q_1 q_2| = (1.6 \times 10^{-19})(3.4 \times 10^{-19})](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fce362edb-c002-49f1-add1-d9933973e98b%2F85131e7e-a657-4050-abb2-c1542583c8de%2F0ux083e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question: Electrostatic Force Calculation
**Problem Statement:**
What is the electrostatic force between a \(1.6 \times 10^{-19}\) C positive charge and a \(3.4 \times 10^{-19}\) C negative charge that are separated by 0.02 m? Use \(8.99 \times 10^9\) N m² C⁻² as Coulomb's constant.
**Answer Choices:**
- **Option 1:** \( 1.22 \times 10^{-24} \, \text{N} \)
- **Option 2:** \( 1.22 \times 10^{-28} \, \text{N} \)
- **Option 3:** \( 1.36 \times 10^{38} \, \text{N} \)
- **Option 4:** \( 1.36 \times 10^{42} \, \text{N} \)
### Explanation:
To solve this problem, use Coulomb's Law, which is given by:
\[ F = k \frac{|q_1 q_2|}{r^2} \]
Where:
- \( F \) is the magnitude of the electrostatic force between the two charges.
- \( k \) is Coulomb's constant, \( 8.99 \times 10^9 \, \text{N m}^2 \text{C}^{-2} \).
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges.
- \( r \) is the separation between the charges.
Given:
- \( q_1 = 1.6 \times 10^{-19} \, \text{C} \)
- \( q_2 = 3.4 \times 10^{-19} \, \text{C} \)
- \( r = 0.02 \, \text{m} \)
Substitute the values into Coulomb's law:
\[ F = 8.99 \times 10^9 \times \frac{|(1.6 \times 10^{-19})(3.4 \times 10^{-19})|}{(0.02)^2} \]
\[ |q_1 q_2| = (1.6 \times 10^{-19})(3.4 \times 10^{-19})
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