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(2-10) A charge q1 = -5 µC is located at (x,y)=(0,3) m. Another charge of q2 = +4 µC is
located at (4.5,3) m.
O (0,0)

9. What is the electric potential due to the charges q, and q2 at the point (4.5, 0) m?

Expert Solution

Step 1

We know that electric potential is calculated as,
$V_{A_{q_{1}}} = \frac{1}{4 π ϵ_{0}} \frac{q_{1}}{r_{1}} V_{A_{q_{} 2}} = \frac{1}{4 π ϵ_{0}} \frac{q_{2}}{r_{2}}$

$r_{1} & r_{2}$ are the distance between $q_{1}$ and A & $q_{2}$ and A respectively.

Here $r_{1} = 5.41 m & r_{2} = 3 m$

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