What is the effect on the emf of the cell shown in figure below, which has the overall reaction Zn(s) + 2H+ (aq) → Zn²+ (aq) + H₂(g), for each of the following changes? Zn anode Anode half-cell- NO₂ Zn²+ NO₂- Submit NO3 Na+ 0.76 V Voltmeter decreases increases NO3 Zn(s) →→→→ Zn²+ (aq) + 2 e¯ 2 H(aq) + 2 e-> H₂(g) Match the words in the left column to the appropriate blanks in the sentences on the right. does not change H₂(8) Cathode half-cell (standard hydrogen electrode, SHE) The pressure of the H₂ gas is increased in the cathode half-cell. As a result, Q increases consequently emf decreases Previous Answers Request Answer Reset Zinc nitrate is added to the anode half-cell. As a result, Qincreases consequently emf decreases X Incorrect; Try Again; 5 attempts remaining You filled in 2 of 8 blanks incorrectly. Sodium hydroxide is added to the cathode half-cell, decreasing [H+]. As a result, increases consequently emf decreases The surface area of the anode is doubled. During this change, Qincreases emf decreases Help
What is the effect on the emf of the cell shown in figure below, which has the overall reaction Zn(s) + 2H+ (aq) → Zn²+ (aq) + H₂(g), for each of the following changes? Zn anode Anode half-cell- NO₂ Zn²+ NO₂- Submit NO3 Na+ 0.76 V Voltmeter decreases increases NO3 Zn(s) →→→→ Zn²+ (aq) + 2 e¯ 2 H(aq) + 2 e-> H₂(g) Match the words in the left column to the appropriate blanks in the sentences on the right. does not change H₂(8) Cathode half-cell (standard hydrogen electrode, SHE) The pressure of the H₂ gas is increased in the cathode half-cell. As a result, Q increases consequently emf decreases Previous Answers Request Answer Reset Zinc nitrate is added to the anode half-cell. As a result, Qincreases consequently emf decreases X Incorrect; Try Again; 5 attempts remaining You filled in 2 of 8 blanks incorrectly. Sodium hydroxide is added to the cathode half-cell, decreasing [H+]. As a result, increases consequently emf decreases The surface area of the anode is doubled. During this change, Qincreases emf decreases Help
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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35. Can u help, please? Not sure which 2 are wrong?
![The image presents a cell diagram with a focus on the effect of various changes on the electromotive force (emf) of a galvanic cell. The overall cell reaction is:
\[ \text{Zn}(s) + 2 \text{H}^+(aq) \rightarrow \text{Zn}^{2+}(aq) + \text{H}_2(g) \]
### Diagram Explanation:
- **Zn Anode:** On the left side, the zinc anode is shown in a solution containing \(\text{NO}_3^-\) and \(\text{Zn}^{2+}\).
- **Cathode Half-Cell (Standard Hydrogen Electrode):** On the right side, the cathode half-cell contains \(\text{H}^+\) ions and gaseous \(\text{H}_2\).
- **Salt Bridge:** A salt bridge containing \(\text{NO}_3^-\) and \(\text{Na}^+\) ions connects the two half-cells.
- **Voltmeter:** A voltmeter is shown measuring the cell potential at 0.76 V.
### Questions and Answers:
1. **Increased \(\text{H}_2\) Pressure:**
- The pressure of the \(\text{H}_2\) gas is increased in the cathode half-cell. As a result, \(Q\) increases, consequently emf decreases.
2. **Adding Zinc Nitrate:**
- Zinc nitrate is added to the anode half-cell. As a result, \(Q\) increases, consequently emf decreases.
3. **Adding Sodium Hydroxide:**
- Sodium hydroxide is added to the cathode half-cell, decreasing \([\text{H}^+]\). As a result, \(Q\) increases, consequently emf decreases.
4. **Doubling Anode Surface Area:**
- The surface area of the anode is doubled. During this change, \(Q\) increases, emf decreases.
The questions highlight how changes in pressure, concentration, and surface area affect the cell's emf by altering the reaction quotient \(Q\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb0be78df-234d-4653-8235-8227b9098990%2F7570accf-e8f9-4397-969c-cb8d702800dc%2F05kxuxxr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The image presents a cell diagram with a focus on the effect of various changes on the electromotive force (emf) of a galvanic cell. The overall cell reaction is:
\[ \text{Zn}(s) + 2 \text{H}^+(aq) \rightarrow \text{Zn}^{2+}(aq) + \text{H}_2(g) \]
### Diagram Explanation:
- **Zn Anode:** On the left side, the zinc anode is shown in a solution containing \(\text{NO}_3^-\) and \(\text{Zn}^{2+}\).
- **Cathode Half-Cell (Standard Hydrogen Electrode):** On the right side, the cathode half-cell contains \(\text{H}^+\) ions and gaseous \(\text{H}_2\).
- **Salt Bridge:** A salt bridge containing \(\text{NO}_3^-\) and \(\text{Na}^+\) ions connects the two half-cells.
- **Voltmeter:** A voltmeter is shown measuring the cell potential at 0.76 V.
### Questions and Answers:
1. **Increased \(\text{H}_2\) Pressure:**
- The pressure of the \(\text{H}_2\) gas is increased in the cathode half-cell. As a result, \(Q\) increases, consequently emf decreases.
2. **Adding Zinc Nitrate:**
- Zinc nitrate is added to the anode half-cell. As a result, \(Q\) increases, consequently emf decreases.
3. **Adding Sodium Hydroxide:**
- Sodium hydroxide is added to the cathode half-cell, decreasing \([\text{H}^+]\). As a result, \(Q\) increases, consequently emf decreases.
4. **Doubling Anode Surface Area:**
- The surface area of the anode is doubled. During this change, \(Q\) increases, emf decreases.
The questions highlight how changes in pressure, concentration, and surface area affect the cell's emf by altering the reaction quotient \(Q\).
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