What is the distance from point to the line 18/0 23 2√6 3 V30 3 P(1,1,1) [2+t] 1-4 = 2-t 3 + 2t

Find the distance between the pair of points(2√3, √6) and (-√3, 5√6). Ifnecessary, express answers in simplified radical form and then round to two decimals places.

Find the area of a triangle formed by the points (8, – 5), (-2, – 7) and (5, 1) by using Herones formula |

Determine the coordinates of the vertex of the square root function below y=16x-10 (0.-10) b) (0,10) (16,–10) c) (4.–10) d)

19) Find the distance between these two points (-8, 5) and (15, -9) Use the formula: d = square root of [(x2– x1)² + (y2 - yı)²]

Use Symmetry qx" Ios°8xdx 17

The distance between the points (3, 8) and (r, 8x + 3) is

point M is the midpoint of JK find the of JK 10X-5 7X +4 M.

Find the distance between the points (−10-10, −14-14) and (−11-11, −8-8)

Subtract. (5x* + 6x° - 2) - (3x - 5x +7) (5x* + 6x° - 2) – (3x2 - 5x +7)=D (Simplify your answer.)