What is the discrepancy (according to an observer on the surface of the Earth), due tothe general relativistic (i.e. gravity-based) time dilation, between the clock on a particularcommunications satellite and a clock on the surface of the Earth after 1 day. Ignore the sign ofthe discrepancy.Orbital Radius of satellite = 4.0 x 10 m6.37 x 106 m%3DRadius of the Earth =Mass of Earth = 5.97 x 1024 kgGravitational Constant = 6.67 x 10-11m3 kg-1 s-2Speed of light =3 x 108 m/s%3D

Given: The orbital radius of the satellite is 4.0×107 m. The radius of the Earth is 6.37×106 m. The…

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