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What is the direction vector of the parametric equation below? x=5+2t y=7-t Z=4 (2,-1,0) (5,7,4) (5,7,0) O (2,-1,4)

What is the direction vector of the parametric equation below? x=5+2t y=7-t Z=4 (2,-1,0) (5,7,4) (5,7,0) O (2,-1,4)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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What is the direction vector of the parametric equation below? x=5+2t y=7-t Z=4 (2,-1,0) (5,7,4) (5,7,0) (2,-1,4)
Transcribed Image Text:What is the direction vector of the parametric equation below? x=5+2t y=7-t Z=4 (2,-1,0) (5,7,4) (5,7,0) (2,-1,4)
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