What is the current read by the ammeter in the circuit below? Let: R1 = 1 kiloohm. R2 = 2 kiloohm. R3 = 3 kiloohm, and the emf of the ideal source is 5 volts. Input R1, R2. and R3 for resistors R1. R2. and R3 respectively. Inpu: E for the emf E. Use context clues to figure out if you need to input a numericol value, varioble, word, etc. All numerical answers should be in three significont figures. R1 R2 R3 (A

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What is the current read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts.
Input R1, R2, and R3 for resistors R1. R2. and R3 respectively. Input E for the emf E. Use context clues to figure out if you need to input a numerical value, varioble, word, etc. All numerical answers
should be in three significant figures.
R1
R2
R3
(A)
First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current:
1= v
R
Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is in milliamperes)
1 = eeec0os
Similarly the current across R2 is:
mA
Transcribed Image Text:What is the current read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts. Input R1, R2, and R3 for resistors R1. R2. and R3 respectively. Input E for the emf E. Use context clues to figure out if you need to input a numerical value, varioble, word, etc. All numerical answers should be in three significant figures. R1 R2 R3 (A) First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: 1= v R Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is in milliamperes) 1 = eeec0os Similarly the current across R2 is: mA
And the current across R3 is:
The current read by the ammeter is the sum of the currents across each resistor:
1=1+12+l3
mA
Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law.
The equivalent resistance of the three resistors in parallel is:
1/Reg =1/R, +1/R2 +1/
Thus.
Reg
Transcribed Image Text:And the current across R3 is: The current read by the ammeter is the sum of the currents across each resistor: 1=1+12+l3 mA Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law. The equivalent resistance of the three resistors in parallel is: 1/Reg =1/R, +1/R2 +1/ Thus. Reg
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