What is the concentration of a 52.30 mL solution of HBr that is completely titrated by 33.50 mL of a 0.200M NaOH solution? [HBr]= M

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**Problem Statement:**

What is the concentration of a 52.30 mL solution of HBr that is completely titrated by 33.50 mL of a 0.200 M NaOH solution?

**Solution:**

To find the concentration of the HBr solution, we can use the formula related to titration:

\[
\text{M}_1 \times \text{V}_1 = \text{M}_2 \times \text{V}_2
\]

Where:
- \(\text{M}_1\) is the molarity of the HBr solution.
- \(\text{V}_1\) is the volume of the HBr solution (52.30 mL).
- \(\text{M}_2\) is the molarity of the NaOH solution (0.200 M).
- \(\text{V}_2\) is the volume of the NaOH solution (33.50 mL).

The balanced chemical equation for the reaction is:
\[ \text{HBr} + \text{NaOH} \rightarrow \text{NaBr} + \text{H}_2\text{O} \]

Since the reaction is a 1:1 ratio, the equation simplifies to:
\[
\text{M}_1 \times 52.30 \, \text{mL} = 0.200 \, \text{M} \times 33.50 \, \text{mL}
\]

Rearranging to solve for \(\text{M}_1\):

\[
\text{M}_1 = \frac{0.200 \, \text{M} \times 33.50 \, \text{mL}}{52.30 \, \text{mL}}
\]

**Enter the Calculated Concentration Below:**

\[
[\text{HBr}] = \text{M}
\]
Transcribed Image Text:**Problem Statement:** What is the concentration of a 52.30 mL solution of HBr that is completely titrated by 33.50 mL of a 0.200 M NaOH solution? **Solution:** To find the concentration of the HBr solution, we can use the formula related to titration: \[ \text{M}_1 \times \text{V}_1 = \text{M}_2 \times \text{V}_2 \] Where: - \(\text{M}_1\) is the molarity of the HBr solution. - \(\text{V}_1\) is the volume of the HBr solution (52.30 mL). - \(\text{M}_2\) is the molarity of the NaOH solution (0.200 M). - \(\text{V}_2\) is the volume of the NaOH solution (33.50 mL). The balanced chemical equation for the reaction is: \[ \text{HBr} + \text{NaOH} \rightarrow \text{NaBr} + \text{H}_2\text{O} \] Since the reaction is a 1:1 ratio, the equation simplifies to: \[ \text{M}_1 \times 52.30 \, \text{mL} = 0.200 \, \text{M} \times 33.50 \, \text{mL} \] Rearranging to solve for \(\text{M}_1\): \[ \text{M}_1 = \frac{0.200 \, \text{M} \times 33.50 \, \text{mL}}{52.30 \, \text{mL}} \] **Enter the Calculated Concentration Below:** \[ [\text{HBr}] = \text{M} \]
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