What is the component form of a vector with a magnitude of 17 and a direction of 125°?

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What is the component form of a vector with a magnitude of 17 and a direction of 125? 
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### Understanding Vector Components

**Question:**
What is the component form of a vector with a magnitude of 17 and a direction of 125°?

---

**Explanation:**

To convert a vector given in magnitude and direction to its component form, you can use the following formulas:

- The x-component (horizontal) of the vector: \( x = R \cos(\theta) \)
- The y-component (vertical) of the vector: \( y = R \sin(\theta) \)

Where:
- \( R \) is the magnitude of the vector.
- \( \theta \) is the direction of the vector, measured in degrees from the positive x-axis.

Given:
- \( R = 17 \)
- \( \theta = 125^\circ \)

Let's calculate the components:

1. **Calculate the x-component:**
   \[
   x = 17 \cos(125^\circ)
   \]

2. **Calculate the y-component:**
   \[
   y = 17 \sin(125^\circ)
   \]

To find the exact numerical values, input the direction angle into a calculator:

- \( \cos(125^\circ) \approx -0.5736 \)
- \( \sin(125^\circ) \approx 0.8192 \)

Therefore:

1. **The x-component:**
   \[
   x = 17 \times -0.5736 \approx -9.75
   \]

2. **The y-component:**
   \[
   y = 17 \times 0.8192 \approx 13.93
   \]

So, the vector in component form is approximately:
\[ 
(-9.75, 13.93) 
\]

This component form corresponds to a vector with a magnitude of 17 and a direction of 125°.
Transcribed Image Text:### Understanding Vector Components **Question:** What is the component form of a vector with a magnitude of 17 and a direction of 125°? --- **Explanation:** To convert a vector given in magnitude and direction to its component form, you can use the following formulas: - The x-component (horizontal) of the vector: \( x = R \cos(\theta) \) - The y-component (vertical) of the vector: \( y = R \sin(\theta) \) Where: - \( R \) is the magnitude of the vector. - \( \theta \) is the direction of the vector, measured in degrees from the positive x-axis. Given: - \( R = 17 \) - \( \theta = 125^\circ \) Let's calculate the components: 1. **Calculate the x-component:** \[ x = 17 \cos(125^\circ) \] 2. **Calculate the y-component:** \[ y = 17 \sin(125^\circ) \] To find the exact numerical values, input the direction angle into a calculator: - \( \cos(125^\circ) \approx -0.5736 \) - \( \sin(125^\circ) \approx 0.8192 \) Therefore: 1. **The x-component:** \[ x = 17 \times -0.5736 \approx -9.75 \] 2. **The y-component:** \[ y = 17 \times 0.8192 \approx 13.93 \] So, the vector in component form is approximately: \[ (-9.75, 13.93) \] This component form corresponds to a vector with a magnitude of 17 and a direction of 125°.
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